Calculate the following line integral

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SUMMARY

The line integral of the vector field \( f(x,y) = (xy, y) \) along the curve \( \gamma(t) = (r\cos(t), r\sin(t)) \) for \( t \in [0, 2\pi] \) evaluates to 0. This conclusion is reached through the application of trigonometric identities and the properties of line integrals. Additionally, the discussion highlights the exploration of potential functions \( u \) such that \( \nabla u = f \), confirming that the integral's value remains unchanged under these conditions.

PREREQUISITES
  • Understanding of vector fields and line integrals
  • Familiarity with trigonometric identities
  • Knowledge of potential functions and gradient operations
  • Basic calculus concepts, particularly in multivariable calculus
NEXT STEPS
  • Study the properties of line integrals in vector calculus
  • Learn about potential functions and their applications in vector fields
  • Explore advanced trigonometric identities relevant to calculus
  • Investigate alternative methods for evaluating line integrals, such as Green's Theorem
USEFUL FOR

Students and educators in mathematics, particularly those focusing on calculus and vector analysis, will benefit from this discussion. It is also valuable for anyone seeking to deepen their understanding of line integrals and vector fields.

lep11
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Homework Statement


Let ##f(x,y)=(xy,y)## and ##\gamma:[0,2\pi]\rightarrowℝ^2##,##\gamma(t)=(r\cos(t),r\sin(t))##, ##r>0##. Calculate ##\int_\gamma{f{\cdot}d\gamma}##.

Homework Equations

The Attempt at a Solution


The answer is 0. Here's my work. However, this method requires that you are familiar with some useful trig identities.
2cpuy6v.jpg


Could someone please take a look at it and check if it's correct? Are there alternative ways? I have also tried to find the potential function ##u##, ##\nabla{u}=f##...
 
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lep11 said:

Homework Statement


Let ##f(x,y)=(xy,y)## and ##\gamma:[0,2\pi]\rightarrowℝ^2##,##\gamma(t)=(r\cos(t),r\sin(t))##, ##r>0##. Calculate ##\int_\gamma{f{\cdot}d\gamma}##.

Homework Equations

The Attempt at a Solution


The answer is 0. Here's my work. However, this method requires that you are familiar with some useful trig identities.
2cpuy6v.jpg


Could someone please take a look at it and check if it's correct? Are there alternative ways? I have also tried to find the potential function ##u##, ##\nabla{u}=f##...

I get an answer of 0 as well, but I have not checked your work because I do not look at posted images, but only at typed versions.
 

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