Engineering Calculate the resistance in the circuit

[Basel H]

Homework Statement

All resistors are $R = 10 \Omega$

Homework Equations

Calculate the total Resistance

The Attempt at a Solution

all resistors are parallel, so
$$ \dfrac{1}{R_{AB}} = \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} $$
$R_{AB} = \dfrac{R}{6}$

 

[CWatters]

Why do you think they are all in parallel? They arent, for example R2 and R3 are in series.

Hint: The circuit has some symmetry. If you applied a voltage to AB what would be the voltage across R6?

 

[cnh1995]

Homework Statement

All resistors are $R = 10 \Omega$
View attachment 217281

Homework Equations

Calculate the total Resistance

The Attempt at a Solution

all resistors are parallel, so
$$ \dfrac{1}{R_{AB}} = \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} + \dfrac{1}{R} $$
$R_{AB} = \dfrac{R}{6}$

Look up 'balanced Wheatstone bridge'.

 

[phinds]

all resistors are parallel ...

As has already been pointed out, this is incorrect. I strongly suggest that you review, several times, the definitions of serial and parallel. Until you have those down cold, you will continue to have problems with circuit analysis.

 

[Babadag]

Since no current will flow through R6 you may delete it [R6].

 

[scottdave]

As @Babadag stated, you can ignore R6. But suppose it was not balanced (or you didn't recognize that). You could do a delta-Y transformation with R2 R4 & R6, to simplify things, if you have learned that.