Calculate the sum of the elements of the U4 set

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The sum of the elements of the U4 set, which consists of the fourth roots of unity {1, i, -1, -i}, is 0. The U set refers to the set of n-th roots of unity, defined as the solutions to the equation x^n - 1 = 0. For any polynomial equation without an "x" term, the sum of the roots equals 0. This principle applies to all n-th roots of unity, confirming that the sum of the elements of Un is always 0. Thus, the sum of the elements of the U4 set is indeed 0.
Taviii
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I saw this problem in a book: calculate the sum of the elements of the U4 set.

The answer is 0, the elements of the sets being: 1, i, -1, -i.

My questions is: what's the U set? :confused:
 
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In this terminology U_{n} refers to the set of the n-th roots of unity, i.e. all roots of the equation

x^{n} - 1 = 0

So

U_{3} = {1, \omega,\omega^2}
 
Thank you!

Your explanation was very helpful.
 
If you multiply out (x-a1)(x-a2)...(x-an) the coefficient of x is easily seen to be -(a1+ a2+ ...+ an) so for any polynomial equation in which there is no "x" term, the sum of the roots must be 0. In particular, the sum of the roots of xn= 1 must be 0 for all n and so the sum of the elements of Un must be 0 for all n.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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