Calculate the tension in the tie-rope between the rod and the wall

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Homework Help Overview

The problem involves a 250-kg block supported by a cable attached to a 100 kg rod that can pivot at its base. The main focus is on calculating the tension in the tie-rope between the rod and the wall, as well as the horizontal and vertical forces at the base of the rod.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the system and question the correctness of the assigned forces. There is a focus on the balance of forces and torques, with some participants suggesting that equilibrium conditions should be considered.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the forces involved. Some guidance has been offered regarding the need to consider torques and the balance of forces, but no consensus has been reached on the correct approach.

Contextual Notes

Participants are working within the constraints of the problem as stated, with an emphasis on understanding the forces and torques without providing complete solutions. There is a mention of an attachment that presumably contains a diagram, but its content is not detailed in the discussion.

Lord Dark
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Homework Statement


Hi again ,, My third Question of the day :
A 250-kg block is supported by a cable attached to a rod of mass 100 kg that can pivot
at the base.
a) Calculate the tension in the tie-rope between the rod and the
wall if it is holding the system in the position shown in Figure.
b) Find the horizontal and vertical forces exerted on the base of
the rod.


Homework Equations





The Attempt at a Solution


in the attachment you'll see the forces I assigned to the system ,, is it right ?? or should I have T2 (above mg) ?? if not I think the question will be too easy:
Fnet(x)=Fh-Tcos(20)
Fnet(y)=Fv+Tsin(20)-mg-Mg (but Tsin(20) = mg) so i can get T and Fv and Fh without even using the Torque ,, so any ideas ??
 

Attachments

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Lord Dark said:
in the attachment you'll see the forces I assigned to the system ,, is it right ??

Where is the force which is acting along the rod? What balances T(cos 20) in your first diagram?
 
Consider the sum of the torques about the pivot.

Equilibrium means that they balance.
 
Shooting Star said:
Where is the force which is acting along the rod? What balances T(cos 20) in your first diagram?

you mean mg ??

LowlyPion said:
Consider the sum of the torques about the pivot.

Equilibrium means that they balance.

yea I got it ,, i thought at first that T(sin20) = mg but now i know what is my mistake ,, thanks guys
 

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