Calculate Time to Complete 1 Revolution from 3.0 rads/s - Help Guide

  • Thread starter Thread starter blackout85
  • Start date Start date
  • Tags Tags
    Homework
Click For Summary
SUMMARY

The discussion focuses on calculating the time required for a wheel to complete one revolution at a rotational speed of 3.0 radians per second. The formula used is derived from the relationship between angular speed and time, specifically using the equation \( \omega = \frac{2\pi}{T} \). By substituting the values, it is established that the time to complete one revolution is approximately 0.477 seconds. The discussion also highlights the rotational speed of the minute hand of a clock, emphasizing the calculation of angular displacement over time.

PREREQUISITES
  • Understanding of angular speed and its units (radians per second)
  • Familiarity with the concept of revolutions and their relationship to radians
  • Basic knowledge of rotational motion equations
  • Ability to perform unit conversions (e.g., seconds to revolutions)
NEXT STEPS
  • Study the derivation of the formula \( \omega = \frac{2\pi}{T} \) in rotational dynamics
  • Learn about angular displacement and its applications in physics
  • Explore the relationship between frequency and period in rotational motion
  • Investigate real-world applications of angular speed in mechanical systems
USEFUL FOR

This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding rotational motion and angular speed calculations.

blackout85
Messages
27
Reaction score
1
If a wheel is turning at 3.0 rads/s, the time it takes to complete one revolution is about:

3.0 rads/s X 1 revolution/6.28 rads = .477 revolutions/s
I just need to get the number of seconds to complete one revolution. Please explain how to go about this just step wise. Thank you.


The rotational speed of the minute hand of a watch is:

w= anglular displacement/ time
w=2pi radian in a circle/ 3600 seconds in one rotation
The reason I put 3600 seconds in the denominator is because it takes that many seconds for the minute hand of a clock to make one full revolution

60minutes X 60second= 3600

Thanks for the help :smile:
 
Physics news on Phys.org
blackout85 said:
If a wheel is turning at 3.0 rads/s, the time it takes to complete one revolution is about:

3.0 rads/s X 1 revolution/6.28 rads = .477 revolutions/s
I just need to get the number of seconds to complete one revolution. Please explain how to go about this just step wise. Thank you.
Use: \omega = 2\pi f = 2\pi/T where \omega is the angular speed in radians/sec, f is the frequency or number of revolutions/sec and T is the time for one revolution.

AM
 

Similar threads

Centripetal Acceleration while Swinging a Stone on a String
  • · Replies 9 ·
Replies
9
Views
2K
Angular Acceleration Homework: 962 Revolutions in 10 Secs
  • · Replies 1 ·
Replies
1
Views
4K
Rotational speed of the minute hand of a watch
  • · Replies 3 ·
Replies
3
Views
9K
Calculating Angular and Linear Speed and period of revolution
  • · Replies 6 ·
Replies
6
Views
2K
Time for Revolution (Rotating about the Center of Mass)
  • · Replies 4 ·
Replies
4
Views
1K
MHB Angular Velocity - 2100 Revs in 3 Mins - 73.3 Rad/s
  • · Replies 4 ·
Replies
4
Views
4K
Time given angular velocity/displacement
  • · Replies 2 ·
Replies
2
Views
5K
Angular Acceleration: 0.29 rad/s/s
  • · Replies 2 ·
Replies
2
Views
2K
Rotating wheel initial angular velocity given final and time
  • · Replies 2 ·
Replies
2
Views
9K
Angular Speed of Clock Minute Hand: Rad/s
  • · Replies 2 ·
Replies
2
Views
2K