Calculate Unbalanced Force to Stop a Car in 3 Seconds

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Homework Help Overview

The problem involves calculating the unbalanced force required to stop a car with a given mass and initial speed within a specified time frame. The subject area pertains to dynamics and the application of Newton's laws of motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions the appropriateness of expressing the force as a negative value, seeking clarification on the meaning of the negative sign in the context of force and acceleration.

Discussion Status

Participants have provided guidance on interpreting the negative sign as an indication of direction rather than a reflection of magnitude. There is a consensus on the understanding that the final answer should be presented as a positive value, focusing on the magnitude of the force.

Contextual Notes

There is an ongoing discussion about the conventions of expressing force and whether the negative sign should be included in the final answer. The original poster's confusion highlights the importance of understanding vector quantities in physics.

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Homework Statement



A car has a mass of 1350 kg and an initial speed of 21 m s-1. Calculate the magnitude of the unbalanced force applied to the brakes that caused the car to come to a halt in 3 seconds.

Homework Equations



Force = mass x acceleration,
= ( 1350 kg ) x ( -7 m s-2 ),
= -9450 kg m s-2
= -9450 N

My question is this, is it ok to write the answer as a negative value of Newtons, as above, because it doesn't seem right? I'm a little confused, any advice would be appreciated.

The Attempt at a Solution

 
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zoezoehzoe said:
My question is this, is it ok to write the answer as a negative value of Newtons, as above, because it doesn't seem right? I'm a little confused, any advice would be appreciated.
Magnitudes are always positive. In this case, the negative sign just indicates the direction--that the acceleration and force were opposite to the velocity.
 
Doc Al said:
Magnitudes are always positive. In this case, the negative sign just indicates the direction--that the acceleration and force were opposite to the velocity.

so

Force = mass x acceleration,
= ( 1350 kg ) x ( -7 m s-2 ),
= -9450 kg m s-2
= 9450 N

would be correct?
 
Yes. Your answer would just be the magnitude--leave off any sign.
 
Doc Al said:
Yes. Your answer would just be the magnitude--leave off any sign.

thank you very much for your help.
 

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