Calculating acc. from the given data

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A car accelerates uniformly, covering 450 meters in the first 5 seconds and 700 meters in the next 5 seconds. Initial calculations incorrectly use average velocity to determine acceleration, yielding 10 m/s². However, this approach is flawed as it does not account for the constant acceleration equations needed for each time interval. A more accurate method involves applying kinematic equations for both segments of the journey. Correctly solving the problem requires a detailed analysis of the motion over the specified time periods.
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Homework Statement



A car moving with uniform acceleration covers 450m in a 5 second interval, and covers 700m in the next 5 seconds interval. The acceleration of the car is ?

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The Attempt at a Solution



please correct me if i am wrong, i calculate velocity at the end of the first run i.e. v1= 450/5= 90m/s . And then at the end of 2nd run v2= 700/5 = 140 m/s. Then i apply,
Acceleration =change in velocity upon time period i.e. (140-90)/5 = 10m/s^2 , right?
Thank you.
 
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hi jatin1990! :smile:
jatin1990 said:
please correct me if i am wrong, i calculate velocity at the end of the first run i.e. v1= 450/5= 90m/s . And then at the end of 2nd run v2= 700/5 = 140 m/s.

nooo, that gives you the average velocity, which doesn't help much :redface:

you'll probably need two constant acceleration equations, one for each time period

(you may find it easier to put t = 0 in the middle, so that the two end-times are ±5 s :wink:)
 
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