Calculating Acceleration and Velocity of a Falling Ball in One Dimension

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A ball is released from the height 3 meters and after it hits the floor it reaches the height 2 meter. A) Whats the speed of the ball in the moment when it meets the ground?
My answer : V^2-V0^2=2gs and here we find V=sqrt60.
What is the speed of the ball in the moment it leaves the ground? V2^2-V^2=2gh2 so V2^2- sqrt60=2g*2 and here we find V2=10
c) If the ball meets the ground for 0.02 seconds what's the direction and numerical value of the acceleration? The direction is upside down and a=(10-sqrt60)/0.02 ARE THESE CORRECT?
 
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Hi Elaia06! :smile:

(try using the X2 button just above the Reply box :wink:)
Elaia06 said:
A ball is released from the height 3 meters and after it hits the floor it reaches the height 2 meter. A) Whats the speed of the ball in the moment when it meets the ground?
My answer : V^2-V0^2=2gs and here we find V=sqrt60.

fine :smile:
What is the speed of the ball in the moment it leaves the ground? V2^2-V^2=2gh2 so V2^2- sqrt60=2g*2 and here we find V2=10

no, that's a constant acceleration formula, so you can't use it "over the bounce" …

try it with final speed 0 :wink:​
 
You mean I should correct the third question,not the second one? maybe you did a little mistake over there?
 
no i did mean the second question (What is the speed of the ball in the moment it leaves the ground?)
 
I attached an image to the reply,it has the formulas for the non constant acceleration..but I don't have the time...
 
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