Calculating Angular Acceleration with Friction on an Inclined Plane

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Homework Help Overview

The problem involves calculating the angular acceleration of a solid uniform cylinder being pulled up an incline while considering the effects of friction. The scenario includes a mass of 5 kg, a pulling force of 45 Newtons, and an incline angle of 30 degrees.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law for rigid bodies and express confusion regarding the correct moment of inertia for the cylinder. Questions arise about the net torque and the role of friction in this context.

Discussion Status

Participants are exploring different interpretations of the moment of inertia and torque. Some guidance has been provided regarding the choice of the axis of rotation and the direction of friction, but no consensus has been reached on the specifics of the calculations.

Contextual Notes

There is uncertainty regarding the direction of the friction force and its relationship to the motion of the cylinder on the incline. Participants are also considering the implications of different axes of rotation on their calculations.

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Homework Statement


A solid uniform cylinder with mass 5 kg is being pulled with a constant force of 45 Newtons up a 30 degree incline. The force is acting on the cylinders center and is parallel to the incline. What is its angular acceleration?

I have a good idea on how to do the problem by using Newtons second law for a rigid body. The only part I'm confused about is on what the moment of inertia should be. I think Its either (.5mr^2) or (.5mr^2 +mr^2)?

please help
 
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im also iffy on the net Torque. I am thinking that friction is the only force causing torque since the 45 N force is acting on the cylinders center.
am i right?
 
Yes. I agree.
 
thanks for the help
 
ripper9100 said:
I have a good idea on how to do the problem by using Newtons second law for a rigid body. The only part I'm confused about is on what the moment of inertia should be. I think Its either (.5mr^2) or (.5mr^2 +mr^2)?
The moment of inertia depends on what you are using as the rotational axis; either expression will work, if you're careful.

ripper9100 said:
im also iffy on the net Torque. I am thinking that friction is the only force causing torque since the 45 N force is acting on the cylinders center.
Again, it depends on the axis of rotation. If you are using the center of mass as the axis, then you are correct.

Even though you have a choice, I recommend using the center of mass of the cylinder as your axis--I think it gives the best understanding of what's going on.
 
what about the friction force is it up the incline or down the incline? I am confused about because usually the direction of friction force is opposite the direction of motion.
 
Remember that friction acts to oppose slipping between surfaces. If there were no friction, which way would the surfaces (cylinder bottom and incline) slip with respect to each other? Use that to figure which way friction must act.
 

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