Calculating Apparent Weight of a Solid Immersed in a Liquid | Homework Help"

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A solid with a density of 5000 kg/m³ weighs 0.5 kg in air and is fully immersed in a liquid with a density of 8000 kg/m³. The discussion revolves around calculating the apparent weight of the solid in the liquid, with confusion arising over the distinction between weight and mass. Participants emphasize the importance of understanding that weight should be measured in Newtons, while mass is in kilograms. Additionally, there are inquiries about graphing the motion of a ball dropping, with suggestions on how to represent the data accurately. The conversation highlights the need for clarity in physics terminology and problem-solving approaches.
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hi


confusing
a solid of density 5000 kg m-3(m raised to 3) weighs 0.5 kg in air
it is completely immersed in a a liquid in a liqiud of density 8000 kg m-3(m raised to three) .
calculate apparent weight of solid in the liqiud

please help as soon as possible
i got to do ma homework
bye

P.S help meeeeeeee:eek: :rolleyes:
 
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hmm...weight is suppose to be in Newton but urs is in kilogram??
 
I need help with graphing!

semc said:
hmm...weight is suppose to be in Newton but urs is in kilogram??


Um.. can you guys help me? I need to know what the graph would look like if I'm graphing the data for a ball droping downwards...
 
Would the slope be going down and would the heights be negative on the graph?
 
hmm...weight is suppose to be in Newton but urs is in kilogram??

Weight is often used synonymously with mass so obviously he is meaning the weight of the object to be the mass of the object. Making the distinction between those two terms is a bit pedantic...AZ_Physics could you maybe shed some light on what information you have at your disposal? I need to know what you are plotting on each axis. Is it speed as a function of the distance from the point of release?
 
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big man said:
Weight is often used synonymously with mass so obviously he is meaning the weight of the object to be the mass of the object. Making the distinction between those two terms is a bit pedantic...

I hope you're not for real, since making the distinction between the terms 'weight' and 'mass' is of essential meaning for anyone who even wants to deal with the letter 'p' of the word 'physics'. :smile:
 
Yes I am for real radou. I probably said it the wrong way though. I meant it's pedantic here in the 'intro to physics'. It's not to say that it isn't important to make the distinction, but when you're dealing with people who do a physics course as just an 'extra' I don't see it as the main point that should be made.

I mean that statement really came across as a smartarse statement. It just said that weight should be in Newtons. It didn't provide him any help or clearly point out that mass is different to weight. So I really wanted to point out that he wasn't being helpful at all.
 
[Edit]
I misunderstood the comments. Forget it.
 
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:blushing: :blushing: :blushing: oops my bad.

I completely misread that question. I thought it was an issue of finding the mass of the submerged part of the object.But it says it is completely submerged. I'm not thinking straight at all tonight. This is pathetic haha.
 
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  • #10
AZ_Physics said:
Um.. can you guys help me? I need to know what the graph would look like if I'm graphing the data for a ball droping downwards...

if you are talking about the v-t graph, assume air resistance is neligible when falling in air, the graph would be y=x until a certain t before it becomes a straight line.for the object falling in liquid, it will be something like a log graph but tends to terminal velocity faster. hope that this helps.
big man said:
I mean that statement really came across as a smartarse statement. It just said that weight should be in Newtons. It didn't provide him any help or clearly point out that mass is different to weight. So I really wanted to point out that he wasn't being helpful at all.
i was trying to know what his 0.5 is referring to...:frown:
 
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