Calculating Armature Current from Active & Reactive Power & Voltage

AI Thread Summary
To calculate the armature current from active and reactive power in a single-phase controlled bridge rectifier supplying a DC motor, use the formulas for RMS active and reactive current based on the voltage. The active power of 1200W and reactive power of 1000VAR can be used to find the apparent power, which is essential for determining the current. While DC motors do not consume reactive power in steady state, the reactive power may be related to components like capacitors in the circuit. The armature current can be approximated as 3.53 A when assuming a large capacitor maintains a near-constant voltage. The discussion emphasizes the importance of understanding the current waveform shape for accurate calculations on the DC side.
ramox3
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How do calculate the current when I have the active power and reactive power and voltage?

A single-phase, full-wave controlled bridge rectifier supplies a permanent magnet dc motor. The rectifier is connected to a 240V ac voltage source and absorbs 1200W of active power and 1000VAR of reactive power from the source. If power loss in the rectifier is negligible how do i calucalte the armature current?
 
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RMS Active Current = Active Power / (RMS Voltage)
RMS Reactive Current = Reactive Power / (RMS Voltage)
 


so what can I say about the value of the current in the armature?
 


I am unsure of what might be consuming the reactive power, perhaps the capacitor Filter you might be using. I don't think DC motor Consume any reactive power during Steady State. So, going with that, all the active power is being consumed by the DC motor.
And the Current Going into it (i.e. into the armature) Depends on whether you are using Capacitor and what size. Assuming you are using Large Sized Capacitor so that the Terminal Voltage Across the Motor is almost constant near the peak of 240*Sqrt(2), then the Current into the armature is
Armature Current = 12000 / (339) = 3.53 A
 


the motor windings are coils they consume reactive power to develop magnetic fields
 


find apparent power with real and reactive then use that to solve for current.

S^2 = root P^2 + Q^2

I = S/root3 V ?
 


FOIWATER said:
the motor windings are coils they consume reactive power to develop magnetic fields
I don't think that's the case for DC motor. Since, they can even overate on Pure DC, there is no way they can consume reactive Power, which occurs only in AC.
 


FOIWATER said:
find apparent power with real and reactive then use that to solve for current.

S^2 = root P^2 + Q^2

I = S/root3 V ?

There is no "sqrt3" as this is a single phase bridge, but otherwise you are correct. But remember that that will only calculate the RMS current on the AC side. If you know the shape of the current waveform however, then from this you can deduce the average current on the DC side.

Lacking any other details, this type of question usually assumes that the current on the DC side is approximately constant due to the motor inductance, so that the line current is a square wave. Given this assumption you can actually calculate both the DC current and the (phase control) firing angle from the given data.
 
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