Calculating Average Force on Proton in Metal Film

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SUMMARY

The discussion focuses on calculating the average force exerted on a proton as it passes through a metal film. Given the proton's mass of 1.67x10^-27 kg, initial speed of 5.0x10^6 m/s, and final speed of 2.0x10^6 m/s after traversing a thickness of 0.010 mm, participants emphasize the relationship between force, mass, and acceleration. The formula for force, F = mass * acceleration, is highlighted, along with the equivalence between energy and force over distance. The key takeaway is that understanding the relationship between initial and final velocities, acceleration, and distance is crucial for solving the problem.

PREREQUISITES
  • Understanding of Newton's second law of motion (F = ma)
  • Basic knowledge of kinematics, specifically uniform acceleration
  • Familiarity with energy concepts, particularly the work-energy theorem
  • Proficiency in unit conversions, especially between meters and millimeters
NEXT STEPS
  • Study the work-energy theorem to understand the relationship between work done and energy changes
  • Learn about kinematic equations for uniformly accelerated motion
  • Explore examples of force calculations in particle physics
  • Investigate the effects of material properties on particle motion through mediums
USEFUL FOR

Physics students, educators, and professionals in fields related to particle physics or materials science who are interested in understanding the dynamics of particles in various media.

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A proton (m=1.67x10^-27 kg) that has a speed of 5.0x10^6 m/s passes through a metal film of thickness 0.010mm and emerges with a speed of 2.0x10^6 m/s. How large an average force opposed its motion through the film??

can anybody give me a clue on where i can start?
 
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Force, F = mass * acceleration.

There is an equivalence between energy and force applied over distance.

If a mass is accelerated uniformly (at an acceleration a) from velocity v1 to velocity v2 over a distance x, what is the relationship between v1, v2, a and x?
 

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