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Average force opposing a proton

  1. Jun 27, 2009 #1
    1. The problem statement, all variables and given/known data

    A proton with mass 1.67 X 10-27 kg that has a speed of 5.0 x10[6] m/s passes through a metal film of thickness .010 mm and emerges with a speed of 2.0 x 10[6]m/s. How large an average force opposed its motion through the film?

    2. Relevant equations

    I'm thinking Newtons second law F=ma will tie into the problem somehow but I'm not sure what equation to use to bring the velocities into the problem.

    3. The attempt at a solution
     
  2. jcsd
  3. Jun 27, 2009 #2

    jgens

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    Gold Member

    Assuming the acceleration is uniform: Vf2 = Vi2 + 2(a)(x)
     
  4. Jun 27, 2009 #3
    Thanks so the plan is to solve Vf2 = Vi2 + 2(a)(x) for a and then use that value of a to solve Newton's second law?
     
  5. Jun 27, 2009 #4

    jgens

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    Gold Member

    Yes.
     
  6. Jun 27, 2009 #5
    Thanks I appreciate your help.
     
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