Calculating Average Power for a Model Train Accelerating from Rest

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SUMMARY

The average power delivered to a model train during acceleration from rest to 0.620 m/s in 21.0 ms is calculated to be 8.01 W. The total mass of the train is 875 g, and the work done is derived from the change in kinetic energy using the formula W_net = K_f - K_i. The calculation confirms that energy conservation principles apply, eliminating the need to compute acceleration directly.

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[SOLVED] simple POWer question

Homework Statement



The electric motor of a model train accelerates the train from rest to 0.620m/s in 21.0ms. Total mass of train 875g.

Find the average power delivered to the train during the acceleration.


Homework Equations



[tex]P_{av}= W_{net}/ \Delta t[/tex]



The Attempt at a Solution



Well..I'm not sure if this is correct...

[tex]W_{net} = K_f- K_i= \Delta K[/tex] ===> I think this is correct but not sure..

using that..

[tex]1/2 mv_f^2 - 1/2 mv_i^2 = 0[/tex]

vi= 0

[tex]1/2 mv_f^2= 0[/tex]

[tex]1/2(.875kg)(0.620m/s)^2 = .1682J[/tex]

P= 0.1682J/ 0.021s= 8.01W====> this seems pretty small but then again it's a model train..is this correct or did I miss something?

I need to know if the way I did the question was correct since they mention acceleration but I'm not sure how would I apply that if I need to at all.

Thank you
 
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That's right. You used energy conservation, so you don't need to compute the acceleration etc.
 
Oh..okay then Thanks Dick :smile:
 

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