Calculating Average Power LCR series circuit

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Homework Help Overview

The discussion revolves around calculating the Q-factor of a series LCR circuit, specifically focusing on determining the average power in the circuit and the role of RMS voltage in the relevant formulas.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the meaning of RMS voltage in the context of average power calculation. Participants discuss the impedance of the circuit and its relation to voltage and current. There is also a question about whether the average power can be expressed in terms of RMS voltage across the resistor.

Discussion Status

Participants are actively engaging with the concepts, providing insights into the relationships between voltage, current, and impedance. Some guidance has been offered regarding the formulas and definitions involved, but no consensus has been reached on the exact interpretation of the RMS voltage in this context.

Contextual Notes

There is an ongoing discussion about the assumptions related to the average power across different components in the circuit, particularly the resistor, inductor, and capacitor.

steejk
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Hi,

Im trying to calculate the Q-factor of a series LCR circuit.

I am struggling at how to calculate the average power. I want to find it using this formula:

pser.gif


What is the RMS voltage in the formula for - is it across the resistor, or what?

Any help is appreciated thanks.
 
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welcome to pf!

hi steejk! welcome to pf! :smile:
steejk said:
What is the RMS voltage in the formula for - is it across the resistor, or what?

from the two denominators, Z2 = R2 + (XL - XC)2

so Z must be the impedance across all three components (R L and C), and so V = IZ is the voltage (potential difference) across all three :wink:

(and V = IZ, so V2 = I2Z2, so Vrms2 = Irms2Z2)
 


tiny-tim said:
hi steejk! welcome to pf! :smile:


from the two denominators, Z2 = R2 + (XL - XC)2

so Z must be the impedance across all three components (R L and C), and so V = IZ is the voltage (potential difference) across all three :wink:

(and V = IZ, so V2 = I2Z2, so Vrms2 = Irms2Z2)

Thanks :)
 


tiny-tim said:
hi steejk! welcome to pf! :smile:


from the two denominators, Z2 = R2 + (XL - XC)2

so Z must be the impedance across all three components (R L and C), and so V = IZ is the voltage (potential difference) across all three :wink:

(and V = IZ, so V2 = I2Z2, so Vrms2 = Irms2Z2)

Can it also be said that Pavg = Vrms(across resistor)/R ?
 
steejk said:
Can it also be said that Pavg = Vrms(across resistor)/R ?

You mean Vrms(across resistor)2/R ?

Yes, the average power across L and C is zero, and the average power across R is VrmsIrms(across resistor) = Vrms(across resistor)2/R :smile:
 

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