Calculating Average Power LCR series circuit

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steejk
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Hi,

Im trying to calculate the Q-factor of a series LCR circuit.

I am struggling at how to calculate the average power. I want to find it using this formula:

pser.gif


What is the RMS voltage in the formula for - is it across the resistor, or what?

Any help is appreciated thanks.
 
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welcome to pf!

hi steejk! welcome to pf! :smile:
steejk said:
What is the RMS voltage in the formula for - is it across the resistor, or what?

from the two denominators, Z2 = R2 + (XL - XC)2

so Z must be the impedance across all three components (R L and C), and so V = IZ is the voltage (potential difference) across all three :wink:

(and V = IZ, so V2 = I2Z2, so Vrms2 = Irms2Z2)
 


tiny-tim said:
hi steejk! welcome to pf! :smile:


from the two denominators, Z2 = R2 + (XL - XC)2

so Z must be the impedance across all three components (R L and C), and so V = IZ is the voltage (potential difference) across all three :wink:

(and V = IZ, so V2 = I2Z2, so Vrms2 = Irms2Z2)

Thanks :)
 


tiny-tim said:
hi steejk! welcome to pf! :smile:


from the two denominators, Z2 = R2 + (XL - XC)2

so Z must be the impedance across all three components (R L and C), and so V = IZ is the voltage (potential difference) across all three :wink:

(and V = IZ, so V2 = I2Z2, so Vrms2 = Irms2Z2)

Can it also be said that Pavg = Vrms(across resistor)/R ?
 
steejk said:
Can it also be said that Pavg = Vrms(across resistor)/R ?

You mean Vrms(across resistor)2/R ?

Yes, the average power across L and C is zero, and the average power across R is VrmsIrms(across resistor) = Vrms(across resistor)2/R :smile: