Calculating Average Power of 130V RMS Generator Circuit

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SUMMARY

The discussion focuses on calculating the average power consumed by a generator circuit with an RMS voltage of 130V, a resistor of 3.65kΩ, and a capacitor of 3.00μF at a frequency of 47.5Hz. The average power formula used is Pavg = (Vrms/Z)VrmsCos(φ), where φ is the phase angle of 17 degrees. The correct average power calculated is 4.23W, with the user initially miscalculating due to an error in determining the impedance (Z). The resolution involved correctly applying the impedance formula and ensuring accurate frequency representation.

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Homework Statement



A generator with an rms voltage of 130V is connected in series to a resistor 3.65k\Omega and a capacitor 3.00\muF.

Using the frequency found in part A (47.5Hz), find the average power consumed by this circuit.

\phi = 17degrees

Homework Equations



Latex isn't working for me so I'm sorry for the formatting

Pavg = (Vrms/Z)VrmsCos(17)

Z=((36502+(1/(2*pi*47.5Hz*3.00*10-6Farad))2)(1/2)

Pavg = (Vrms/Z)VrmsCos(17)

Pavg = .1111 W

The answer is 4.23 W

I'm just trying to figure out where I went wrong.
 
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It's hard to tell where you went wrong because you haven't supplied much in the way of intermediate results. For example, what value did you get for Z, the magnitude of the impedance?

When I compute (Vrms/Z)VrmsCos(17) I get the expected answer.
 
After punching it through again I got the correct answer; I went wrong in the way I set up Hz; punching in 47.5^-1, since Hz = S^-1; but that's redundant...
 

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