Calculating Biconvex Glass Lens Radius of Curvature for a +35-cm Focal Length

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Discussion Overview

The discussion revolves around calculating the radius of curvature for a biconvex glass lens with a specified focal length of +35 cm. Participants explore the application of the lens maker's equation in this context.

Discussion Character

  • Homework-related

Main Points Raised

  • A participant presents a calculation using the lens maker's equation, suggesting a radius of curvature of 50 cm, but expresses doubt about the correctness of this answer.
  • Other participants note that the question fits within the homework category and suggest it should be moved to the appropriate forum for such inquiries.

Areas of Agreement / Disagreement

There is no consensus on the correctness of the calculation provided, and the discussion primarily focuses on the categorization of the question rather than resolving the calculation itself.

Contextual Notes

Participants have not clarified any assumptions regarding the lens parameters or the application of the lens maker's equation, and there may be unresolved steps in the calculation process.

Roof
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Question: A biconvex glass (n = 1.70) thin lens is to have a +35-cm focal length. If the radius of curvature of each surface is measured to be the same, what must it be? Give your answer in cm to two decimal places.

My answer:
I used this equation 1/f=(n-1)*(1/r1+1/r2), I got an answer 50cm. Am I right or I missing somthings? still doubt
 
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I think this should be in the homework question section.
 
Thanks richyw
 
Indeed, questions like this (solutions to specific exercises, whether they are actually assignments for a course or not) belong in one of the "Homework and Coursework Questions" forums. In this case, the "Introductory Physics" is the appropriate one.
 

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