Calculating Centripetal Force: 40.0kg Child on 9.0m Ferris Wheel

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To calculate the force exerted by the seat on the child on the Ferris wheel, first determine the child's weight, which is 392 N (40 kg x 9.8 m/s²). The centripetal force required for circular motion is calculated using the formula F = mv²/r, where m is mass, v is velocity, and r is radius. The child rotates four times per minute, translating to a velocity of approximately 9.42 m/s. The total force exerted by the seat is the sum of the child's weight and the centripetal force, resulting in a seat force of 397 N, which is 5 N more than the child's weight.
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A 40.0 kg child on a Ferris wheel rotates four times each minute and the wheel has a radius of 9.0 m.

What force does the seat exert on the child when the child is halfway between the top and bottom?

The answer is 397 N which is 5 N more than the weight of the child, but I have not idea how they got that, anyone have any ideas?
 
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HINT: The seat also supplies the centripetal force to keep the child moving in a circular path.
 
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