Calculating Centripetal Force: Diagramming and Solving for X and Y Forces

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Centripetal force can be expressed as F=(mv^2)/r, which can be demonstrated through diagramming and analyzing the forces in the x and y directions. The work done by centripetal force in the radial direction is calculated as the product of the force magnitude and displacement in the same direction. Since the force and displacement vectors are perpendicular in uniform circular motion, the angle between them is 90 degrees, resulting in zero work done. This means that while centripetal force maintains circular motion, it does not perform work on the object. Understanding these relationships is crucial for solving problems related to centripetal force and motion.
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How would you go about proving that centripetal F=(mv^2)/r by diagramming and solving for the magnitude of the forces in the x and y direction?

For example, suppose I wanted to calculate the work done in the radial direction by centripetal force.
 
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Thanks so much! Really helpful
 
Work is the product of the applied force magnitude x the magnitude of the displacement (D) in the same direction as the applied force. As a result, this is sometimes expressed as W = F x Dcosθ where θ is the angle between the two vectors (F and D). Since the F and D vectors are always perpendicular for circular motion of a mass at a constant speed, the angle between the two vectors is always 90°. So, the work done in circular motion at constant speed is 0 since cos90° is 0.
 
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