Calculating Cliff Height from Sound Time Delay | Kinematics Question

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To calculate the height of a cliff from which a rock is dropped, the total time of 3.2 seconds includes both the fall time of the rock and the time for the sound to travel back to the observer. The speed of sound is given as 340 m/s, allowing for the calculation of the distance sound travels in that time. The rock's fall time can be expressed as (3.2 - t) seconds, where t is the time taken for the sound to reach the observer. The equations of motion for the rock's fall must be applied to find the height of the cliff. This problem involves combining kinematic equations with the time delay of sound to determine the cliff's height accurately.
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Homework Statement


A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.2s later. If the speed of sound is 340 m/s, how high is the cliff.



Homework Equations


d= v1t + 1/2at^2
v2^2 = v1^2 + 2ad



The Attempt at a Solution


I tried using d = vt since we're given the speed of sound and the time taken for the sound to reach our ears. Since sound is unaffected by gravity, i thought i could straightaway use that formula, but I guess I was wrong. This is how far I got up to. Can someone give me a hand?

Thanks
 
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You can use d=vt for the sound. However, note that we are told that 3.2s after the rock is dropped, we hear it hit the ocean, not that the sound takes 3.2s to reach our ears.

Use d=vt to obtain the time taken for the sound to reach out ears iafter the rock hits the ocean(in terms of d). We then know that the rock takes (3.2-t)s to fall. Can you write another equation for the rock as it falls?
 
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