Calculating Conveyor Belt Capacity: Solving a Work and Power Problem

[DethRose]

Hey i have another work and power problem that i have no idea what to do on

this one states

a conveyor belt is driven by a motor rated at 35 kW. Only 73% of the rated power is available to do useful work. The coal is to be raised and deposited into a hopper 21.1 m above. How many kilograms of coal can be delivered per minute.

i found that the motor is 25.55 kW at 73% but that's as far as i got lol

help please

 

[NateTG]

Hey i have another work and power problem that i have no idea what to do on

this one states

a conveyor belt is driven by a motor rated at 35 kW. Only 73% of the rated power is available to do useful work. The coal is to be raised and deposited into a hopper 21.1 m above. How many kilograms of coal can be delivered per minute.

i found that the motor is 25.55 kW at 73% but that's as far as i got lol

help please

How much energy does it require to move 1 kg of coal up 21.1 m?

 

[dextercioby]

Hey i have another work and power problem that i have no idea what to do on
this one states
a conveyor belt is driven by a motor rated at 35 kW. Only 73% of the rated power is available to do useful work. The coal is to be raised and deposited into a hopper 21.1 m above. How many kilograms of coal can be delivered per minute ?
i found that the motor is 25.55 kW at 73% but that's as far as i got lol
help please

Power is work/time=force*velocity.From here u can say that
P=\frac{F\cdot h}{t}=\frac{mg\cdot h}{t}\Rightarrow \frac{m}{t}=\frac{P}{gh}
The rate (mass carried per second) is:
\frac{25550W}{9.80665ms^{-2} 21.1m} approx.=123Kg/s

I'll let u compute the mass carried in one minute.

Daniel.