Calculating Current in Thevenin Equivalent Circuit?

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Discussion Overview

The discussion revolves around calculating the current in a Thevenin equivalent circuit. Participants explore methods for determining the Thevenin resistance and current using Kirchhoff's Current Law (KCL) and circuit analysis techniques.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses uncertainty about calculating the current I and questions the use of KCL at a specific node.
  • Another participant suggests finding the Thevenin resistance by deactivating all sources and measuring the equivalent resistance between two points.
  • A different participant proposes using KCL at node A to solve for I, but expresses discomfort with the approach.
  • One participant corrects the equation setup for KCL, emphasizing the importance of direction for the current source.
  • A final participant indicates they have resolved their confusion after the discussion.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to calculate the current I, and there are differing opinions on the application of KCL and the setup of equations.

Contextual Notes

There are unresolved assumptions regarding the circuit configuration and the specific values of node voltages, which may affect the analysis.

john88
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I trying to figure out a thevenin equivalent circuit

I want to calculate the current I so I can't get the resistance for the thevenin equivalent.

Im not 100% sure how to calculate I, can I use KCL on the node under the number -8.7V?

http://img98.imageshack.us/my.php?image=curfc7.jpg
 
Last edited:
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That sure is a complex circuit. To find Rth, kill all the current and voltage sources and then measure the equivalent resistance between A&B.

KCL is valid everywhere. Is that -6.7 and -8.7 node voltages given by the question? If so, then you can easily find Isc. Also note that the 1mA source is connected in parallel with a short-circuited wire.
 


so if short circuit the system. Can I setup KCL on node A and then solve for I,
I = I(source) + I(R10).

But it seems odd to do so.
 


You got the equation wrong. It's IR10 = Isource + I. Be careful of the direction designated for Isc.
 


ok, got everything together now, ty for the help!
 

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