Calculating Current Through JFET Transistor System

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To calculate the current through a JFET transistor system with a grounded source and a reverse-biased gate at 3V, the drain circuit includes a 2000-ohm resistor in series with a 20V potential. The reverse bias reduces the channel size, increasing resistance and affecting current flow. The expected current through the load resistor is 2mA, leading to a total resistance of 10,000 ohms when factoring in the series resistor. The voltage across the source-drain channel is crucial for confirming this current calculation. Understanding the family of curves for the specific JFET model may provide additional insights for accurate analysis.
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I have a problem of calculating the current through a system. It is a simple JFET transistor with the source grounded. The gate is reverse biased with a 3v potential, and the drain has a 2000 ohm resistor in series then a positive 20v potential in series which is of course grounded. How would I go about finding the current through the load resistor?
 
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...Assuming an n-type Si transistor

Also I don't have any other information.. I know that the more and more you apply a negative voltage on the gate, the smaller the channel gets which leads to more resistance across the source-drain channel. The answer I am lookin for is 2mA.. that would lead to a resistance of 8000 ohms, cause we still have a 2000 ohm resistor in series therefore 10000 ohm and with a voltage across the source-drain channel of 20 volts.. you get your 2mA answer, I don't see how you can get this bridge voltage without knowing something about a family of curves or the like?
 
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