Calculating Current With Capacitor

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To calculate the current flowing through a 4 µF capacitor connected to a 240V, 50 Hz supply, the reactance (XC) is first determined using the formula XC = 1/(2πfC). The calculation yields XC = 796.178 ohms. To find the current, the formula I = V/XC can be applied, where V is the voltage across the capacitor. The discussion highlights the importance of correctly calculating XC and using it to derive the current. Understanding these concepts is essential for solving capacitor-related problems in AC circuits.
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Homework Statement


c) Calculate the current flowing when a 4 uF capacitor is connected across 240V 50 Hz supply ?



Homework Equations



XC = 1/(2πfC)


The Attempt at a Solution



XC = 1/(2πfC)
XC = 1/(2π 50*0.000004)
XC = 1/(2π* 0.0002)
XC = 1/(6.28* 0.0002)
XC = 1/ 0.001256
XC = 0.001256

I'm not sure if this is correct. I would appreciate it if anyone could help me out. Thanks in advance !
 
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licklecee said:

Homework Statement


c) Calculate the current flowing when a 4 uF capacitor is connected across 240V 50 Hz supply ?



Homework Equations



XC = 1/(2πfC)


The Attempt at a Solution



XC = 1/(2πfC)
XC = 1/(2π 50*0.000004)
XC = 1/(2π* 0.0002)
XC = 1/(6.28* 0.0002)
XC = 1/ 0.001256
Good so far.
XC = 0.001256
Nope. Do you see the error?

XC = 1/0.001256 = ______ ?​

Once you have the reactance XC, you still need to find the current as asked for.
 
Ahh okay thank you !,

So Xc = 796.178

Now i know the reactance how i can get the current ? i haven't been able to find a formulae for it.

Thank you in advance !
 
Here is a hint: the units of XC are Volts/Amps.
 
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