Calculating Curve Line in a Graph: An Example

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Discussion Overview

The discussion revolves around calculating the curve line in a graph, specifically related to the trajectory of a skier. Participants explore the application of the equation v = d/t and seek clarification on how to interpret the graph provided, which lacks proper labeling and clarity.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant asks for an example of calculating the curve line using the equation v = d/t.
  • Another participant critiques the graph for being unclear, noting that the axes are not labeled and multiple elements are plotted on the same vertical scale.
  • A participant acknowledges the limitations of their diagram, indicating it was created in a basic program and seeks clarification specifically about the trajectory line.
  • One reply provides a link to a resource related to gravity, which may not directly address the original question.
  • Another participant shares personal insights about skiing dynamics, emphasizing that the slope of the hill and forward velocity significantly affect the fall, suggesting that time, speed, and distance computations may not be directly applicable in this context.

Areas of Agreement / Disagreement

Participants express differing views on the clarity and relevance of the graph, with some questioning its utility while others attempt to clarify their understanding of the trajectory. There is no consensus on how to approach the calculation or the interpretation of the graph.

Contextual Notes

The discussion highlights limitations in the provided graph, including missing labels and the accuracy of the diagrams. The relationship between the skier's dynamics and the graph's representation remains unresolved.

Pin Head
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Hi,
Ho do I calculate for the curve line in this graph I understand that I use this equation
v = d/t.Could anyone show me an example?
 

Attachments

  • trajectory.JPG
    trajectory.JPG
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Pin Head said:
Hi,
Ho do I calculate for the curve line in this graph I understand that I use this equation
v = d/t.Could anyone show me an example?

Your graph is meaningless. The axes are not labelled, but more importantly, you're plotting 3 different things all with the same vertical scale! It makes no sense.

Zz.
 
Hi sorry about that unfortunately I've had to design these diagrams in paint so they are not that accurate , but what I would like to know is about the line that curves which is title trajectory,The other thing is is that the diagram that made no sense was from a physics example I was gave to use So hopefully the diagrams I've made make a bit more sense
 

Attachments

  • acceleration.JPG
    acceleration.JPG
    4.9 KB · Views: 471
  • trajectory.JPG
    trajectory.JPG
    6.6 KB · Views: 407
  • velocity.JPG
    velocity.JPG
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here, let me google that for you: http://www.engineeringtoolbox.com/accelaration-gravity-d_340.html" .
 
Last edited by a moderator:
But what does this have to do with a skier falling down. I rarely do a time, speed distance computation when I fall while skiing. However, based on some personal experience, the hill's slope has a significant impact on the dynamics of the fall. Also the forward velocity (or more correctly the velocity along the skiing surface) influences the the dynamics. Unless this is associated with jumping, the velocity normal to the surface, which is typically at a significant angle to the horizontal, is fairly low.
 

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