Calculating Distance and Time for Two Cars on a One-Dimensional Road

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Homework Help Overview

The discussion revolves around a problem involving two cars traveling on a one-dimensional road, with one car passing a point at time t=0 and the second car passing the same point 5 seconds later. The participants are tasked with determining when the second car meets the first and the distance between them at that moment.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equations of motion for both cars and how to set them equal to find the meeting time. There are questions about the interpretation of the distance between the cars and how it is maintained until they meet.

Discussion Status

The conversation includes attempts to clarify the problem statement and the equations used. Some participants express confusion regarding the phrasing of the distance question, while others question the logic behind maintaining a distance that is decreasing as the cars approach each other.

Contextual Notes

There are indications that the original problem statement may be poorly translated, leading to misunderstandings about the distance question. Participants are navigating these ambiguities while trying to align their interpretations with the problem requirements.

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An automobile which travels with the constant speed 20 m/s passes in a section in the moment t=0s and 5 seconds later in the same section passes another automobile which travles with the speed of 30 m/s in the same direction.a) Find when the second car meets the first one.
My solution : x1=x2 20t=30(t-5) and here we find t=15 seconds.b) Whats the distance between the cars since the section until they meet? How to do this one? Just give me an idea..
 
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Hi Elaia06! :smile:

hmm :confused:

ahh! o:), i think you mean …​
Elaia06 said:
An automobile which travels with the constant speed 20 m/s passes a line at time t=0s and 5 seconds later another automobile which travels with the speed of 30 m/s in the same direction passes the same line.
a) Find when the second car meets the first one.
My solution : x1=x2 20t=30(t-5) and here we find t=15 seconds.b) Whats the distance past the line when they meet?

your equations should be …
x1 = 20t
x2 = 30(t-5)
x1 = x2 :wink:

you already have t = 15,

so x1 = x2 = … ? :smile:
 
I did it this way, but my teacher said it was not correct O.o Now I logged in physicsforum and I see we have the same opinion :S Even the other students had done it this way.Whatever,thank you :)
 
Hi Elaia06! :smile:

Please remember that I rewrote the question so that it fitted your solution!

Perhaps the question means something different?
 
So the distance question means " The two cars,since they pass the line have a distance.They keep this distance until they meet.Find the distance.This is basically what I did,found that distance.
 
Elaia06 said:
" The two cars,since they pass the line have a distance.They keep this distance until they meet.Find the distance.

sorry, but that doesn't make any sense :redface:

(how can they keep the distance if the distance is getting smaller?)
 
Thats what it says in my book,literally.I am not english and the book I work with is translated poorly ..Whatever,thank you anyway..
 

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