Calculating Distance Given Work and Forces

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The discussion revolves around calculating the distance a hay wagon travels based on the work done and forces involved. A farmhand performs 972 J of work while pulling the wagon with a force of 310 N at an angle, opposed by a frictional force of 280 N. The initial calculation incorrectly used the work done by the farmhand instead of the net work. The correct approach requires using the net force to determine the distance, leading to the conclusion that the distance traveled is 3.4 m, which does not account for friction. The clarification emphasizes the importance of using net work in such calculations.
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Homework Statement



A farmhand does 972 J of work pulling an empty hay wagon along level ground with a force of 310 N [23 degrees below the horizontal]. A frictional force of 280 N opposes the motion. The distance the wagon travels is
a. 0.39 m
b. 1.7 m
c. 3.4 m
d. 32 m
e. 1.8 x 102 m

Homework Equations



W=FcosΘd
Fnet=F1+F2

The Attempt at a Solution



W=Fd
d=W/F
d=972/(310cos23-280)
d=180 m

Apparently, the correct answer is c) 3.4 m, which works if you don't account friction, but I don't understand how that's correct.
 
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Natko said:

Homework Statement



A farmhand does 972 J of work pulling an empty hay wagon along level ground with a force of 310 N [23 degrees below the horizontal]. A frictional force of 280 N opposes the motion. The distance the wagon travels is
a. 0.39 m
b. 1.7 m
c. 3.4 m
d. 32 m
e. 1.8 x 102 m

Homework Equations



W=FcosΘd
Fnet=F1+F2

The Attempt at a Solution



W=Fd
d=W/F
d=972/(310cos23-280)
d=180 m

Apparently, the correct answer is c) 3.4 m, which works if you don't account friction, but I don't understand how that's correct.

You have divided the work done by the farmhand by the net force . If you are going to use the net force, you need to use the net work, not the work done by the farmhand.
 
I was wrong
 
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