Calculating Distance of Runners from Flagpole When Paths Cross

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Runner A starts 5.6 km west of a flagpole and runs east at 8.7 km/h, while Runner B starts 4.2 km east of the flagpole and runs west at 7.4 km/h. To find the point where their paths cross, the total distance between them is calculated, and their combined speeds are used to determine the time it takes to meet. After solving the equations, the distance from the flagpole when they cross is approximately 0.304 km. Some participants expressed confusion over the calculations and the expected precision of the answer. Ultimately, the correct distance when their paths intersect is confirmed to be around 0.304 km.
alexistheman
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Runner A is initially 5.6 km west of a flagpole
and is running with a constant velocity of
8.7 km/h due east. Runner B is initially 4.2
km east of the flagpole and is running with a
constant velocity of 7.4 km/h due west.

How far are the runners from the flagpole
when their paths cross? Answer in units of
km.


How do i even start this, I am stuck.
 
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Drawing the scenario is always a good place to start.
R1------------------------------F-------------------------R2
Now you're looking for when R1 and R2 pass each other. That means what?
 
displacement by chance?
 
Like i drew it out, but when i do i still don't know how to set it all up. I am so stumped. :(
 
I got .3 KM but it says its wrong.. ugh
 
The runners will pass each other. This would happen after t hours. So that means that after t hours both runners will be at the same spot (not the same distance ran).
-Basically, at some time t, the two runners x position will be equal.
 
8.7 km/h + 7.4 km/h = 4.7 km + 5.6 km

16.1 km/h = 9.8 km

t = 9.8 km / 16.1

t=.608695652

8.7 * .608695652 = 5.29565213

5.6 - 5.29565213 = .30434782

your answer is .30434782 buddy
 
Hm, confusing. lol. I set it up and got 5.29 but ugh wouldn't it be .31
 
alexistheman said:
Hm, confusing. lol. I set it up and got 5.29 but ugh wouldn't it be .31
Why don't you post what you did.
 
  • #10
Ugh it wanted the full number, thanks ~.~
 
  • #11
it was operator and stupid website error lol
 
  • #12
happens..i had trouble on this one early tonight but i figured it out..
 
  • #13
well thanks man, heh.
 
  • #14
no prob.
 

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