Calculating Drug Amount in a Capsule with Given Density Function and Dimensions

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Homework Help Overview

The discussion revolves around calculating the volume and drug amount in a capsule, focusing on the geometry of the capsule and a given density function. The subject area includes calculus and integration in the context of three-dimensional geometry.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the volume calculation of the capsule and the application of a density function. There are attempts to convert Cartesian coordinates to cylindrical polar coordinates, with questions about the appropriate substitutions for variables x, y, and z.

Discussion Status

Participants are exploring different methods to approach the problem, including integration and coordinate transformation. Some guidance has been offered regarding the use of cylindrical coordinates, and there is an ongoing examination of the implications of these transformations on the density function.

Contextual Notes

There is a mention of the capsule's dimensions and the specific density function provided, which may influence the calculations. Participants are also considering the need for integration in their approach.

DanBNyberg
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The question is asked in 3 parts. The first asks for the volume within the capsule.

The capsule has a radius=2mm total length=10mm, each end is rounded with r=2mm.
I have found the volume to be 108.9mm

The second part of the question gives a density function of the drug inside of the capsule.
It asks for the amount of drug inside of the capsule. The funtion is:

δ(x,y,z)=1/(6pi^2cosh5)* e^(-z)/root(4-x^2-y^2)

The capsule is oriented around the z axis, centered at the origin. Can you help me find what values to use for x,y,z,? Thanks!
 
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This problem is probably easiest to approach using cylindrical polar co-ordinates. Try to remember how to convert x,y,x into r theta and z and the values to use should be obvious.
 
Is this where I chould head?
z=z
x=rcos theta
y=rsin theta

those substitutions into the denominator would give me:
root(4-(2cos theta)^2-(2sin theta)^2)
then:
root(4-4(cos^2 theta + sin^2 theta))
root(4-4(1))

I think I am off track again, I am getting root 0.
 
try again. Think integration rather than substituting in numbers.

Express r in terms of x and y, can you see that expression in the question?
 
Thanks for the help. So, I should integrate the function and convert to polar for the solution?
 

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