Calculating Efficiency of a DC Motor: How Do I Determine In and Out Values?

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Discussion Overview

The discussion revolves around calculating the efficiency of a DC motor, focusing on the appropriate formulas for determining input and output power. Participants explore the definitions and relationships between power, work, and energy in the context of motor efficiency, with an emphasis on torque and RPM calculations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Homework-related
  • Experimental/applied

Main Points Raised

  • One participant questions the teacher's formula for Power In, suggesting it should involve a different variable to accurately represent energy over time.
  • Another participant points out that the formula for Power Out resembles the gravitational potential energy equation, indicating a potential misunderstanding in equating power with energy.
  • There is a proposal that Power In could be expressed as PE/T = mgh/t, while Power Out might be calculated as torque multiplied by RPM.
  • Concerns are raised about ensuring the units for torque and RPM are compatible to yield correct power units (watts or horsepower) for Power Out.
  • One participant clarifies that the inquiry is for an experimental report rather than homework, indicating the context of the discussion.

Areas of Agreement / Disagreement

Participants express differing views on the correct formulas for calculating input and output power, with no consensus reached on the appropriate equations. The discussion remains unresolved regarding the correct approach to calculating efficiency.

Contextual Notes

Participants highlight potential issues with unit compatibility and the need for conversion factors, as well as the importance of distinguishing between power and energy in their calculations.

cavalierean
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Hi I am trying to calculate the efficiency of my DC motor. I know that efficiency is:

Power Out / Power In * 100

I have been told by my teacher that Power In is calculated by the following formula,

Power In = Power * Time

And Power Out is;

Power Out = Mass * Gravity * Height.

I think that there is an error here in what he has given us. First of all I believe that we need to calculate work in and work out for efficiency. To do so we would need torque and RPM calculations for Work Out? And I'm not sure about Work In. Also I believe these equations he has given us have contradictory units and hence are incorrect.

Could anyone tell me how I would calculate efficiency and what equations would I need for In and Out values. And if it was torque and RPM what equation would I use, using these two to calculate the Out value.

Thanks,
 
Last edited:
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Power In = Power * Time

Well, that doesn't seem right , does it.

With SI units,
Power is measured in watts, which is J/s ( Joules/second ).
Joules is a unit of energy.
Power = Energy / Time
Power Out = Mass * Gravity * Height.
That also is to annoying.

The terms multiplied on the right hand side look amazingly the same as gravitational potential energy, which is measured in joules.In both cases, your notes incorrectly equate power to energy.

Work, by the way, in a measurement of energy.

Perhaps your equations in your notes should be:
( Can you figure out what the correct equations should be )
Hint:
For the input power you have to change one of the terms to something else.
For power out you have to decide by another variable.

Also, for electrical circuits, if you measure the volts and the amperage going into the motor, what do you get? energy in or power in?
 
So... would it be

Power In = PE/T = mgh/t ?

and

Power Out = torque x RPM ?

?

(The original equation is what my teacher gave me) haha
 
Last edited:
need to know asap
 
Power In = PE/T = mgh/t

Does a falling mass run your motor?
You might mean Power Out.

What about volts and amps input into you motor for Power In?

Power Out = torque x RPM
That is generally correct.
You just have to be sure your units for torque and RPM are a matchup so that they multiply correctly to give watts or horsepower for the Power Out. You might need a conversion factor.

By the way, if this is homework, which it appears to be, there is a Homework Section which is great for exercise questions.
 
no this is for an experimental report.
anyway thank you very much for the help
 

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