Calculating Electron Orbit Radius in a Magnetic Field

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SUMMARY

The discussion focuses on calculating the radius of an electron's orbit in a magnetic field of 5.76 mT, given an angular momentum of 6.10 x 10-26 kg m2/s. The relevant equations include F = mv2/r and F = QRB, where Q is the charge of the electron and B is the magnetic field strength. The user attempted to solve the problem by substituting variables but encountered errors in their calculations. Clarification on the substitution process is requested to resolve the issue.

PREREQUISITES
  • Understanding of classical mechanics, specifically angular momentum.
  • Familiarity with the Lorentz force equation (F = QRB).
  • Knowledge of circular motion and centripetal force concepts.
  • Basic proficiency in algebra for manipulating equations.
NEXT STEPS
  • Review the derivation of the Lorentz force equation in electromagnetic contexts.
  • Study the relationship between angular momentum and radius in circular motion.
  • Learn about the charge-to-mass ratio of an electron and its implications in magnetic fields.
  • Practice solving similar problems involving charged particles in magnetic fields.
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in the dynamics of charged particles in magnetic fields.

kmikias
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Homework Statement


An electron orbits in a 5.76 mT field with an angular momentum of 6.10 x 10-26 kg m2/s. What is the radius of the orbit (in m)?


Homework Equations


F = mv2/r
F= QRB


The Attempt at a Solution


MV2/r = qrb
v = wr
so i plugged and my answer is still wrong .any help please
 
Physics news on Phys.org
Can you show us exactly what you plugged into what and how? Then we should be able to help you.
 

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