# Calculating Emitter Current - Voltage-Divider Bias

1. Jun 20, 2014

### ?n0t_A_nUmb3R?

I am aware that there are two methods of working out IE for a Voltage-Divider circuit.

The first is:
And then work out VE = VB - VBE

And the second is:
(VTH and RTH)

I then tried to calculate a specific problem using both methods. The results were not consistent and varied.
My question is can we use both methods (first and second above) interchangeably?
Are there any differences between the two methods?

Last edited: Jun 20, 2014
2. Jun 20, 2014

### Staff: Mentor

Then please show what you did and which setup you mean. Otherwise it is hard to tell what went wrong.

3. Jun 23, 2014

### ?n0t_A_nUmb3R?

There is a difference of 0.31mA. Is this still acceptable?
Can I also use these methods interchangeably? (Voltage Divider Method and VTH/RTH Method)

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• ###### My Answer (Collector Current).pdf
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4. Jun 23, 2014

### Staff: Mentor

I don't understand your equation for IE. A difference of 6% is a bit large for rounding errors.

5. Jun 23, 2014

### ?n0t_A_nUmb3R?

As I know it to be, it is basically simplifying the circuit using Thevenins Theorem.
Problem is I don't know where to use it.
From the examples I've worked it seems as if I can use this method OR the voltage divider method.
But in some instances, there is a considerate difference in my calculations.
My lecturer is out of office at the moment. So unfortunately I cannot email him.

#### Attached Files:

• ###### Thevenins Equivalent.pdf
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6. Jun 23, 2014

### ?n0t_A_nUmb3R?

I do realize that the Thevenins method is for loading effects and the voltage-divider method is for unloaded effects. But I have come across questions where they do not mention whether the circuit is loaded or not.

7. Jun 23, 2014

### Staff: Mentor

You must inevitably arrive at the same answer, unless you make different or wrong approximations along the way, or through oversight or blunder.