Calculating Energy from Mass Using E=mc²

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Homework Help Overview

The discussion revolves around calculating energy from mass using the equation E=mc², specifically focusing on the conversion of mass units and the implications of using different units in energy calculations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the addition and subtraction of masses in grams, the need for unit conversion to kilograms, and the application of E=mc². Questions arise regarding the assumptions made about the number of reacting atoms and the appropriate units for energy calculations.

Discussion Status

Guidance has been offered regarding unit conversions and the importance of understanding the definitions of joules. Participants are exploring the implications of their calculations and clarifying their understanding of the problem setup.

Contextual Notes

There is a focus on ensuring that mass is expressed in the correct units for energy calculations, and participants are encouraged to consider the ratios of reactants rather than assuming a single atom reaction.

ElegantSir
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Homework Statement


I have the question with a diagram posted in the thumbnail to make things easier.

Homework Equations


E = mc²

The Attempt at a Solution


The homework only had a single example for a question like this so I am not 100% sure how to get the answer. So far I've added the 2 masses:
5.030151g and 5.011267g

Then I subtracted them both 5.030151 – 5.011267 = 0.018884g

Here is where I am stuck. I know that from the example I need to do something like 1.8884 * 10^(input some number here) but I have no clue how to get the number that it should be to the power to. All I know is after this I need to multiply 1.8884 * 10 ^ (?) by 3.8 * 10 ^ 8 to calculate the total amount of energy produced using E = mc²
 

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ElegantSir said:

Homework Statement


I have the question with a diagram posted in the thumbnail to make things easier.

Homework Equations


E = mc²

The Attempt at a Solution


The homework only had a single example for a question like this so I am not 100% sure how to get the answer. So far I've added the 2 masses:
5.030151g and 5.011267g

Then I subtracted them both 5.030151 – 5.011267 = 0.018884g

Here is where I am stuck. I know that from the example I need to do something like 1.8884 * 10^(input some number here) but I have no clue how to get the number that it should be to the power to. All I know is after this I need to multiply 1.8884 * 10 ^ (?) by 3.8 * 10 ^ 8 to calculate the total amount of energy produced using E = mc²
Why are you assuming that the masses of the elements reacting are not in grams?

I think you are assuming, based on the wording of the question, that only 1 atom of D and T react, but that need not be the case. Only the ratios of the reactants matter.

Also, units should be carefully scrutinized here. If you take c in m/s, what mass units must you use in order to calculate energy in joules?
 
SteamKing said:
Why are you assuming that the masses of the elements reacting are not in grams?

I think you are assuming, based on the wording of the question, that only 1 atom of D and T react, but that need not be the case. Only the ratios of the reactants matter.

Also, units should be carefully scrutinized here. If you take c in m/s, what mass units must you use in order to calculate energy in joules?
Im not quite sure what you mean by all of that. I assume you mean I need to convert grams to a different unit of measurement but I am not sure what. Also what do you mean by
"I think you are assuming, based on the wording of the question, that only 1 atom of D and T react?"
 
ElegantSir said:
Im not quite sure what you mean by all of that. I assume you mean I need to convert grams to a different unit of measurement but I am not sure what.

Well, joules are the SI units of energy. Joules are also derived units. What is the definition of a joule?

https://en.wikipedia.org/wiki/Joule

Also what do you mean by
"I think you are assuming, based on the wording of the question, that only 1 atom of D and T react?"

It's obvious that 1 atom of deuterium does not have a mass of 2.014102 g, but a certain number of deuterium atoms does have this total mass. Ever heard of a fellow by the name of Avogadro?

https://en.wikipedia.org/wiki/Avogadro_constant

If you're going to study physics, you've got to study units and understand how units are useful in deciphering physics problems.
 
SteamKing said:
Well, joules are the SI units of energy. Joules are also derived units. What is the definition of a joule?

https://en.wikipedia.org/wiki/Joule
It's obvious that 1 atom of deuterium does not have a mass of 2.014102 g, but a certain number of deuterium atoms does have this total mass. Ever heard of a fellow by the name of Avogadro?

https://en.wikipedia.org/wiki/Avogadro_constant

If you're going to study physics, you've got to study units and understand how units are useful in deciphering physics problems.
Ahh I see where I went wrong. The example
 
Ahh I see where I went wrong. The example questions like to use numbers like 1.9 * 10^-4 rather than use the actual whole number so I got confused.

I would need to convert grams to kilograms which would mean the number would now become: 1.8884 * 10^-5
Now I plug it into E = mc^2 and get:

E = 1.8884 * 10^-5 * (3 * 10^8)^2
E = 1.7 * 10 ^ 12 (rounded of course)

Im assuming this is the correct answer now?
 
ElegantSir said:
Ahh I see where I went wrong. The example questions like to use numbers like 1.9 * 10^-4 rather than use the actual whole number so I got confused.

I would need to convert grams to kilograms which would mean the number would now become: 1.8884 * 10^-5
Now I plug it into E = mc^2 and get:

E = 1.8884 * 10^-5 * (3 * 10^8)^2
E = 1.7 * 10 ^ 12 (rounded of course)

Im assuming this is the correct answer now?
Always include the units in your calculation results. That's a habit you should acquire now.
 
SteamKing said:
Always include the units in your calculation results. That's a habit you should acquire now.
Ahh yes it would be in Joules...Thanks for the help!
 

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