Calculating Energy Stored in a Metallic Object in a Magnetic Field

In summary, the energy in a soft iron sphere in an originally uniform magnetic field B_0 is given by U=(1/8\pi)\int B^2d^r.
  • #1
rsr_life
51
0
Hi!

I'd like to know if there is some way of computing or deriving the energy stored in a metallic object subject to a magnetic field from external sources?

Say, an iron cylinder or a sphere in a magnetic field (that is uniform or non-uniform). What is the energy in the cylinder because of this external magnetic field? Is there some formula that I can use or some concept or site that I can look at to understand this? Been stuck with this for a while and my results don't look right.

Appreciate any help in advance.
 
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  • #2
Btw, I'd appreciate a strong mathematical description (link, theory, idea), etc. Am a grad student, so the math itself isn't the problem. Just the concept, taking into account interface conditions, etc. I assume that's how it's done in PF? Suggestions are always welcome.
 
  • #3
The energy depends on the geometry of the object, among other things.
A soft iron sphere in an originally uniform magnetic field B_0 is probably the easiest case.
The magnetization in the sphere is uniform, given by M=3B_0/4pi (in Gaussian units).
This is found in the same way as for a dielectric sphere in a uniform electric field.
The magnetic energy is given by [tex]U=(1/8\pi)\int B^2d^r[/tex],
for which I get U=B_0^2R^3/4pi.
 
  • #4
Thanks for that Pam,

But what is the basic relation that I derive this from? I'd like to do it for a cylinder and for some other shapes too. Wouldn't the field depend on the angle that each small area makes with the external field?

And is that integrand B^2*d^r? What's that notation?
 
  • #5
I was a bit careless, The integral should be
[tex]U=(1/8\pi)\int {\vec B}\cdot{\vec H}d^3r[/tex].
However, since H~0 inside a high mu sphere, the integral is for all space outside the sphere where B=H, so the B^2 is correct here.
The problem for a soft iron sphere is just the same as for a dielectric sphere in an electric field, which is done in most EM books. Then, the B field for r>R is just that of a dipole.
The energy is very shape dependent. For a long narrow cylinder aligned with the B_0 field, or for a disk, the calculation is also fairly simple.
The procedure is:
Use the standard electrostatic methods, just letting E-->H, D-->B, P-->M, epsilon-->mu
to find B, H, and M. Then do the integral over B.H.
For more complicated, shapes, the first step becomes very complicated.
 
  • #6

Related to Calculating Energy Stored in a Metallic Object in a Magnetic Field

1. How do you calculate the energy stored in a metallic object in a magnetic field?

The energy stored in a metallic object in a magnetic field can be calculated using the formula E = 1/2 * m * B^2 * A, where m is the mass of the object, B is the magnetic field strength, and A is the cross-sectional area of the object.

2. What is the unit of measurement for energy stored in a metallic object in a magnetic field?

The unit of measurement for energy stored in a metallic object in a magnetic field is usually joules (J).

3. How does the shape of the metallic object affect the calculation of energy stored in a magnetic field?

The shape of the metallic object can affect the calculation of energy stored in a magnetic field as it determines the cross-sectional area (A) used in the formula. A larger cross-sectional area will result in a higher energy stored.

4. Can the energy stored in a metallic object in a magnetic field be negative?

No, the energy stored in a metallic object in a magnetic field cannot be negative. It is always a positive value as it represents the potential energy of the object in the magnetic field.

5. How does the strength of the magnetic field affect the energy stored in a metallic object?

The strength of the magnetic field directly affects the energy stored in a metallic object. As the magnetic field strength increases, the energy stored also increases according to the formula E = 1/2 * m * B^2 * A.

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