Calculating Equation of Evolute for Catenary Curve

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Ok, so i need to calculate the equation of the evolute for the catenary
\gamma(t)= (t,cosh(t)).
I'm not really sure how to do this, the definition of evolute I have requires a unit-speed parametrization, but it looks a little difficult to find that also (the arclength if I'm correct is given by
s(t)=\frac{1}{2}(sin(2t)+t)).

Is there some "standard" way of finding the evolute?
 
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You are NOT correct about the arclength (did you confuse cosh(t) with cos(t)?).

if \gamma(t)= (t, cosh(t)) then the arclength is given by \integral\sqrt{1+ sinh^2(t)}dt= \integral cosh(t)dt= sinh(t)[/itex].
 
Yeah, i made a boo boo calculating the arclength :redface: . And apparently the definition i was given for the evolute of a unit-speed curve can also be used for any other parametrization of the curve, so everything's a-okay. :smile:
 
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