Calculating Escape Velocity for Earth: Where Am I Going Wrong?

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The discussion revolves around a user struggling to calculate Earth's escape velocity correctly. They initially use the formula but arrive at an incorrect value of 353,541 m/s instead of the known 11.2 km/s. The user realizes that they mistakenly used an incorrect radius value and confirms that the radius should be in meters. After clarification, they acknowledge the oversight in units and express gratitude for the assistance. The conversation highlights the importance of unit consistency in physics calculations.
breid040
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Homework Statement
Find the escape energy of earth. Earth's radius is 6378km, its mass is 5.976x10^24kg, and the universal gravitational constant is 6.67x10^-11
Relevant Equations
vescape=Sqrt(2MG/r)
I really cannot understand where this is going wrong...
Plugging in the constants, I get
vescape=Sqrt(2(6.67x10^-11)(5.976x10^24kg)/6378).

(6.67x10^-11)(5.976x10^24kg) gives me 3.99x10^14, and multiplied by 2 gives me 7.97x10^14.

7.97x10^14/6378=1.25x10^11.
The square root of 1.25x10^11 would give 353541 m/s. I know that this is not right, as the escape velocity of Earth is 11.2 km/s.

If I divide 2MR by 6378000, then it gives me the correct answer... but this is not the radius of the earth. I genuinely am stumped. I've typed this carefully into my calculator many times. Help is greatly appreciated.
 
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When substituting for r, what should be the units for r?
 
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TSny said:
When substituting for r, what should be the units for r?
Ah. Meters. Thanks so much... can't believe I missed that!
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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