Calculating Flow Rate in Horizontal & Vertical Pipes

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SUMMARY

The discussion centers on calculating the volume flow rate in a system of horizontal and vertical pipes. The scenario involves a liquid flowing through a horizontal pipe with a radius of 0.02m that bends upward 10.0m to join another horizontal pipe with a radius of 0.04m. The key equation used is Bernoulli's equation, which relates pressures and velocities at two points in the flow. The solution involves setting the pressures equal and recognizing the relationship between the velocities, leading to a solvable equation.

PREREQUISITES
  • Understanding of Bernoulli's equation
  • Knowledge of fluid dynamics principles
  • Familiarity with the concept of incompressible flow
  • Basic algebra for solving equations
NEXT STEPS
  • Study Bernoulli's equation in detail
  • Learn about fluid flow in pipes and the impact of pipe diameter on velocity
  • Explore the concept of pressure drop in vertical pipes
  • Investigate applications of fluid dynamics in engineering
USEFUL FOR

Students in physics or engineering courses, professionals in fluid mechanics, and anyone involved in designing or analyzing piping systems.

raywang5
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Homework Statement


A liquid is flowing through a horizontal pipe whose radius is 0.02m. The pipe bends staight upward through a height of 10.0m and joins another horizontal pipe whose radius is 0.04m.


Homework Equations


what volume flow rate will keep the pressures in the two horinontal pipes the same?

The Attempt at a Solution


i tried to use p1+1/2xpxv1^2+pgh1=p2+1/2xpxv2^2+pgh2..
any idea?
 
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raywang5 said:

Homework Statement


A liquid is flowing through a horizontal pipe whose radius is 0.02m. The pipe bends staight upward through a height of 10.0m and joins another horizontal pipe whose radius is 0.04m.


Homework Equations


what volume flow rate will keep the pressures in the two horinontal pipes the same?

The Attempt at a Solution


i tried to use p1+1/2xpxv1^2+pgh1=p2+1/2xpxv2^2+pgh2..
any idea?


I think you are dealing with the same formula I found in a Physics text:

p_1 + rho*(v_1)^2/2 +rho*g*y_1 =
p_2 + rho*(v_2)^2/2 +rho*g*y_2

Set y_1 = 0, y_2 = 10m, set p_1 = p_2 = p, and we know v_1 = v_2/4 (assuming incompressible flow)

and we are left with one equation and one unknown. Note the p's cancel along with the rho's.
 

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