Calculating Flux on a Curved Surface in Cylinder Coordinates

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SUMMARY

The discussion focuses on calculating the flux of the vector field F = < x + y^3, y, z - y^3 > through the curved surface of a solid defined in cylindrical coordinates with parameters r [0,1], theta [0, pi], and z [0, 2]. The normal vector is identified as n = < x, y, 0 >, leading to the expression F*n = 1 + xy^3 for the flux calculation. The differential surface area element dS is discussed, with the conclusion that it simplifies to 1 dx dy, although the integration should be performed over the variables theta and z.

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Homework Statement



The following vector field is given: F = < x + y^3, y, z - y^3 >

Let T be the solid given in cylinder coordinates by: r [0,1], tetha [0, pi], z [0, 2]

Find the flux out of the curved part of the surface of T.

2. The attempt at a solution

The normal vector n is < x, y, 0 >

F*n is therefore 1 + xy^3

Then I need dS = sqrt(1 + zx2 + zy2) dx dy. Is this simply 1 dx dy?
 
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But x and y aren't the variables you are going to integrate over, are they? Don't you want to integrate over theta and z? (You are sort of right, in the sense that dS is independent of the integration variables, if you choose them correctly).
 

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