Calculating Focal Length of a Converging Lens Using Incident and Refracted Rays

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To calculate the focal length of a converging lens using incident and refracted rays, the angles of incidence and refraction are essential. The total distance from point A to B is 75.3 cm, which can be expressed as the sum of the object distance (do) and the image distance (di). Using the tangent of the angles provided, the relationships between do and di can be established. By solving the resulting equations, the values for do and di can be determined, leading to the calculation of the focal length using the lens formula 1/d0 + 1/di = 1/f. This approach effectively combines geometry and trigonometry to find the focal length of the lens.
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Homework Statement


The figure illustrates qualitatively a converging lens focusing monochromatic rays from A to B. The vertical and horizontal scales of the figure are not the same. The top ray leaves A at an angle of 2.38 deg above the optic axis and leaves B at an angle of 1.25 deg below the optic axis. The total distance from A to B is 75.3 cm.

http://i32.photobucket.com/albums/d2/NikkiNik88/convLens3.gif

Calculate the focal length of the lens for that light.



Homework Equations



1/d0 + 1/di = 1/f



The Attempt at a Solution



I'm not even sure where to begin when I'm given the angles. I think 75.3 cm = d0 + di
but I'm not sure where to go from there
 
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Hi NikkiNik! :smile:

This is a geometry exercise …

you have two triangles, you know the lengths a+b and h, and you know a/h and b/h. :wink:
 
If AOP is the axis of the lens, and AP and BP are the incident and refracted rays, then OP/do = tan 2.38 and BP /di = tan 1.25.
Or do*tan2.38 = di*tan1.25
And do + di is given.
Find do and di and hence focal length of the lens.
 
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