Calculating force for a mass in a hoop

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SUMMARY

The discussion focuses on calculating the force exerted by a mass M (0.640 kg) sliding inside a hoop of radius R (1.60 m) at an angle of 37.0°. The initial speed of the mass at the top of the hoop is 5.25 m/s. The incorrect attempts at calculating the force highlight the necessity of determining the speed of the mass at the specified angle before applying Newton's second law. The correct approach involves using the centripetal acceleration formula and adjusting for the angle to find the accurate force exerted on the hoop.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of centripetal acceleration (a=v²/r)
  • Basic trigonometry, specifically tangent functions
  • Familiarity with force diagrams and free-body diagrams
NEXT STEPS
  • Calculate the speed of the mass at an angle of 37° using energy conservation principles.
  • Learn about centripetal force and its application in circular motion problems.
  • Explore the relationship between gravitational force and normal force in inclined scenarios.
  • Study the effects of friction in circular motion and how it alters force calculations.
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Physics students, educators, and anyone interested in understanding dynamics in circular motion and force calculations in mechanical systems.

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Homework Statement


A mass M of 6.40E-1 kg slides inside a hoop of radius R=1.60 m with negligible friction. When M is at the top, it has a speed of 5.25 m/s. Calculate the size of the force with which the M pushes on the hoop when M is at an angle of 37.0°.

[URL]http://loncapa.gwu.edu/res/msu/physicslib/msuphysicslib/13_EnergyConservation/graphics/prob25_1015hoop2.gif[/URL]

Homework Equations


Finding the F


The Attempt at a Solution



i tried 2 times and both are wrong

first i tried

a=v^2/r
a=(5.25)^2/1.6
a=17.227

F=ma
F=(.640)(17.227)
F=11.025N and that's wrong...

second try i draw force diagram and got

tan(37)=opposite/adjacent
tan(37)mg=opposite
4.726N=the horizontal force of the gravity? and its wrong.
 
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Smartguy94 said:
first i tried

a=v^2/r
a=(5.25)^2/1.6
a=17.227
You're using the speed at the top. But you need the speed at 37°. Figure that out first.

(FYI: Your diagram is not viewable.)
 

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