Calculating Force on a Stretched Steel Rod | Young's Modulus 200*109 Pa

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To calculate the force on a stretched steel rod, the relevant parameters include a length of 250 cm, a diameter of 0.254 cm, and a stretch of 0.85 cm, with Young's Modulus for steel at 200*10^9 Pa. The correct force calculated is 3400 N using the formula F/A = Y(ΔL/L0). There is confusion regarding the area calculation, as it is not provided in the problem statement. Posting detailed calculations can help clarify the issue. Accurate area determination is crucial for solving the problem correctly.
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A cylindrical steel rod is originally 250 cm long and has a diameter of 0.254 cm. A force is applied longitudinally and the rod stretches 0.85 cm. What is the magnitude of the force? The value for Young's Modulus for steel is 200*109 Pa.
The correct answer is 3400 N, i used the equation F/A=Y(ΔL/L0) but kept getting some weird numbers. I think I'm screwing up on finding the area, since in most of the problems the area is already given. Can someone help me figure this out?
 
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fightboy said:
A cylindrical steel rod is originally 250 cm long and has a diameter of 0.254 cm. A force is applied longitudinally and the rod stretches 0.85 cm. What is the magnitude of the force? The value for Young's Modulus for steel is 200*109 Pa.
The correct answer is 3400 N, i used the equation F/A=Y(ΔL/L0) but kept getting some weird numbers. I think I'm screwing up on finding the area, since in most of the problems the area is already given. Can someone help me figure this out?

Things will go much easier if you post your calculations, so says the Magic 8-Ball. :smile:
 

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