- #1

Perodamh

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## Homework Statement

A cylindrical rod of copper (E = 110GPa) having a yield strength of 240MPa is to be subjected to a load of 6660N. If the length of the rod is 380mm, what must be the diameter to allow an elongation of 0.5mm.

## Homework Equations

E = stress/ strain

stress = Force/Area ; Area = pi*(diameter)/4

strain = elongation/original length

E= young's modulus = 110GPa = 110 * 10^9Pa

yield strength = 240MPa = 240 * 10^6Pa

Force = 6660N

elongation = 0.5mm

original length = 380mm

## The Attempt at a Solution

I'm trying to understand relation between yield strength and young modulus.So far all i got from google is that it is the max stress a body goes through before plastic deformation occurs, but how do i plug that in anywhere? Thanks