Calculating Forces and Acceleration in a Two-Block System

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The discussion focuses on calculating the forces and tension in a two-block system involving masses M (5 kg) and m (4 kg) with an acceleration of 2 m/s². The coefficient of friction between mass M and the table is 0.2, which affects the calculations. Participants emphasize the importance of applying Newton's second law separately to each mass to derive the correct equations for force and tension. There is a suggestion to draw free body diagrams for clarity and to ensure the equations account for all acting forces. The conversation highlights the need for careful distinction between the two masses to avoid errors in solving the problem.
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Homework Statement



The constant force that works in the object M=5 kg forces the object with mass m=4 kg to move with acceleration a=2 m/s^2.
The coefficient of friction between M and the table is 0.2.
Determine
a)F=? b) T=?

Homework Equations

The Attempt at a Solution


SOLUTION:
F-Ff=(m)*a Here I find F
and here I find F
B) F-(T+Ff)=m*a or T=m2*g ;G-T=m*g

Picture to help you http://i1171.photobucket.com/albums/r549/Elaia06/jh.jpg

Edited: Maybe it is F-Ff=(m+M)*a where Ff =M*g*0.2?
 
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Draw a free body diagram of each mass separately (one for m and one for M). For the mass on the table, there is another force besides F and F-f acting in the x direction. For the hanging mass there are 2 forces acting. Use Newton 2 for each and solve the 2 equations for the 2 unknowns.
 
I know,its also the tension but I want to know if my equations are written in the right way?
 
They are not. First distinguish between m and M. Write your force equations for each block.
 
I edited it
 
Do not solve it this way. You will be headed for trouble. Look at each block separately please.
 
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