Calculating G-Force in Ski Jumping: 40m Radius, 37 to 9 Degrees

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In ski jumping, the g-forces experienced during the innrun can be calculated using the provided data: a 40-meter radius, an initial angle of 37 degrees, and a final angle of 9 degrees, with speeds ranging from 85 km/h to 93 km/h. The maximum g-force at the lowest point of the curve, where velocity is highest, is estimated to be 2.7 G, resulting from 1.7 G due to centripetal acceleration and 1 G from gravity. The angle change from 180 degrees to 152 degrees would not significantly affect the g-forces experienced. The highest g-forces occur at the bottom of the curve due to the combination of gravitational and centripetal forces. Understanding these dynamics is crucial for skijumpers to gauge the physical demands of their sport.
xvillix
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Hello, I´m a skijumper and wondering the amount of g-forces I am put through in the innrun.
So this is the data:

Radius 40 meter
Angel before the curve 37 degrees
Angel after the curve 9 degrees
Speed 93 km/h
The speed at the start of the curve is probably 85 km/h and 93 km/h at the end.

Can someone calculate the amount of g-forces please?

Would the amount of g-forces been different if you would have gone from 180 degrees to 152 degrees. Or does the angel of where you are have nothing to say?

Thank you.
 
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Highest g-forces will always be at the very bottom of the curve, because that's where Earth's gravity adds directly with the force due to centripetal acceleration, as well as being the point of highest velocity.

Assuming that 93km/h is good estimate for speed at the lowest point (the 9° after that shouldn't make a big difference) you'd be pulling max of 2.7 G. (1.7 from curvature + 1 from gravity).
 
Thank you
 
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