Calculating g with centripetal acceleration

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Discussion Overview

The discussion revolves around calculating the acceleration due to gravity (g) using the formula for centripetal acceleration, specifically in the context of the Earth's rotation. Participants explore the relationship between centripetal acceleration and gravitational force, examining the implications of their calculations and the underlying physics concepts.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant attempts to calculate g using the formula a = w^2 * r, providing specific values for angular velocity and Earth's radius, but questions the validity of their result.
  • Another participant argues that the formula used does not yield g but rather the net acceleration required to maintain an object on the Earth's surface in a circular path, highlighting the role of gravitational and normal forces.
  • A different participant clarifies that the calculation represents centripetal acceleration for an object moving in a circle at the Earth's radius, which is not equivalent to g.
  • One participant points out that the calculation reflects centrifugal force experienced at the Earth's equator due to rotation, not gravitational acceleration.
  • Another participant emphasizes that gravity arises from mass attraction rather than rotational motion, indicating that non-spinning masses also exert gravitational forces.

Areas of Agreement / Disagreement

Participants generally disagree on the interpretation of the centripetal acceleration calculation and its relation to gravitational acceleration. There is no consensus on the validity of the initial approach or the implications of the results.

Contextual Notes

Participants express uncertainty regarding the assumptions made in the calculations and the definitions of forces involved, particularly in distinguishing between centripetal and centrifugal forces.

dmayers94
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Hi, I'm trying to find g, or 9.8 m/s^2, with the formula a = w^2 * r. First, I found the value for the angular velocity (2*pi/24 hours) and i converted this to radians per second finding the value 2*pi/86400. I googled the radius for the Earth and got 6,378,100 meters. Finally, i plugged these values into the formula to obtain a centripetal acceleration of 0.0337 m/s^2 which obviously isn't the answer I was looking for. Can someone find the holes in my math or logic? Thanks.
 
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I haven't checked the numbers, but that formula won't give you g anyway. It will instead give you the net acceleration required to keep an object on the Earth's surface moving in the circular path given by the Earth's radius. At the Earth's surface, both the gravitational force and the normal force of the ground act on objects. What you have found is the difference between the accelerations caused by these two forces.

If gravity were the only force acting on an object at the Earth's surface, it would be pulled down into a much tighter "orbit." One with a radius much smaller than earth's. But this is not possible since contact forces with the ground counteract gravity somewhat, and they balance so that we stay on the surface of the Earth at all times.
 
This formula is not supposed to give you g.

you get g at a distance R from the Earth's centre using g=GM/R^2

where M is mass of earth
G is the Universal Gravitation constant.
For g at surface we use R as radius of earth.

What you are calculating by a=w^2*R is something entirely else.

You have calculated the centripetal acceleration felt by a particle moving in a circle of radius R at the same angular frequency as that of earth.

That has no reason to be g.

Infact its the centripetal acceleration a person on equator will have wrt to the Centre of Mass of Earth (but we don't feel as we are at rest relative to Earth's surface and because its too small) cause we are rotating with earth.
 
Last edited:
Gravity is caused by masses attracting each other and not because they are spinning. Non-spinning objects attract each other just as well as spinning objects.
 

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