Calculating Gas Pressure in a Nebula with 100 Atoms/cm^3 and 7500 K Temperature

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Homework Help Overview

The discussion revolves around calculating the gas pressure in a nebula, which contains a low density of gas at 100 atoms/cm³ and is heated to a temperature of 7500 K. The original poster seeks to determine the gas pressure in atmospheres.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of atoms to moles and question the calculations leading to the derived pressure value. There is an exploration of the implications of low gas density in interstellar space and how it affects pressure.

Discussion Status

Some participants have provided checks on the calculations and confirmed the original poster's results, suggesting that the derived pressure value may be reasonable given the context. However, there is no explicit consensus on the accuracy of the calculations.

Contextual Notes

Participants note the significance of the temperature and density of the gas in relation to typical values for interstellar space, indicating that the low pressure is expected in such environments.

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Homework Statement


A nebula-- a region of the galaxy where new stars are forming contains a very tenuous gas with 100 atoms/ cm^3. This gas is heated to 7500 K by the uv radiation from nearby stars. What's the gas pressure in atm?


Homework Equations





The Attempt at a Solution



100 atoms * 1mol/6.022*10^23 atoms = 1.02 * 10^-16 moles
1 cm^3 * (1m/100cm)^3 = 1 * 10^-6 m^3
R= 8.31 J/mol K
pV=nRT
p(10^-6 m^3) = (1.02 * 10^-16 mol)(8.31)(7500 K)
p= 1.03 * 10 ^-11 Pa = 1.02 * 10 -16 atm Does this seem too small to you?
 
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bcjochim07 said:
100 atoms * 1mol/6.022*10^23 atoms = 1.02 * 10^-16 moles

How did you divide 100 by Avogadro's number and get 10^-16?

p= 1.03 * 10 ^-11 Pa = 1.02 * 10 -16 atm Does this seem too small to you?

We are talking about interstellar space here. The pressure is going to be very low...

Here's a check you can do. The molar volume of an ideal gas at STP (about 300 K) is 22.4 liters, so there is roughly 0.05 mole/L or 5 x 10^-5 mole/cc . This is 25 times hotter, so that would lower the number of moles by a factor of 25, which would be 2 x 10^-6 mole/cc ; that's still at 1 atmosphere. How many atoms are in the one c.c. at this point?

If you reduce the number of atoms to 100, what does the pressure become? That will give you the order of magnitude (and maybe one sig-fig) of the pressure.

EDIT: That suggests that your answer is OK, but you mistyped your number of moles...
 
Last edited:
oops it should be the 1.66 * 10 ^ -22, that was the answer I typed in as moles. I came up with the answer correctly though. Other than that it looks fine?
 
The check I describe confirms your result. So it seems to be just fine...
 

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