Calculating GPE of a 500lb Weight Lifted 40'

  • Context: High School 
  • Thread starter Thread starter RobVG
  • Start date Start date
  • Tags Tags
    Gpe Weight
Click For Summary

Discussion Overview

The discussion revolves around calculating the gravitational potential energy (GPE) of a 500 lb weight lifted vertically by 40 feet, with participants exploring the relationship between work done and GPE, as well as the appropriate units for measurement.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant asks for help in calculating the GPE of a 500 lb weight lifted 40 feet, assuming work done equals GPE.
  • Another participant questions the clarity of the question, suggesting it lacks sufficient information to calculate an absolute GPE and implies that the change in GPE is what should be calculated.
  • Some participants argue that the question is fine, noting that GPE is commonly used and that the height change is clear.
  • Concerns are raised about the mixing of units, with one participant emphasizing the need to convert Imperial units to metric for proper calculation.
  • A participant points out that Newtons are a unit of force, not energy, and clarifies that the weight of 500 lbs represents the force due to gravity acting on the object.
  • Another participant explains that to find the increase in potential energy, one must multiply the known force by the distance lifted, but suggests converting units to metric for the final answer in joules.
  • Discontent arises from a participant who feels misunderstood and expresses frustration at perceived rudeness in responses, while others attempt to clarify their points and encourage patience in the discussion.

Areas of Agreement / Disagreement

Participants express differing views on the clarity of the original question, the appropriateness of the units used, and the relevance of height in the context of force versus energy calculations. No consensus is reached regarding the framing of the question or the responses provided.

Contextual Notes

There is a noted confusion regarding the distinction between force and energy units, as well as the implications of using different measurement systems. Some participants highlight the need for conversions to ensure accurate calculations.

RobVG
Messages
3
Reaction score
0
This is probably child's play for you guys but can you show me how to figure the gpe of a 500lb weight lifted straight up 40'? In joules?

I assume the work done is equal to the gpe?

Thank guys
 
Physics news on Phys.org
RobVG said:
This is probably child's play for you guys but can you show me how to figure the gpe of a 500lb weight lifted straight up 40'? In joules?

I assume the work done is equal to the gpe?

Thank guys

I conjecture that "gpe" is an acronym for "gravitational potential energy". If this is true, then the increase in "gpe" is equal to the work.
This is a a badly posed question. Not only is it being asked using an obscure acronym. In addition, your are not asked about the change in gpe. You are being asked as though there is an absolute quantity called gpe.
There isn't enough information given in the problem to calculate the absolute gpe. To answer the question quantitatively, one has to make a guess as to what the examiner was asking. One has to hypothesize that what is being asked for is the change in gpe. Only than one can say that the answer is the work.
A badly posed question can throw experts. Especially experts! So you have no reason to be embarrassed.
 
I think the question is posed fine. GPE is used as an acronym here all the time and 40' is a clear change in height.
 
The question is fine, but it's a trick question in the sense that the units are mixed.

The Joule is the SI, or metric, unit of energy. This is equivalent to work done.

The question is posed in Imperial "British" units of inches and pounds.

Convert inches to metres (one inch=2.54 centimetres) and pounds to Kg (1 lb = .454 Kg) and use your wits to find the gravitational field strength of Earth as I don't want to do your homework for you and then multiply the mass, the vertical displacement and the gravitational field strength together to get the work done.
 
Granted - as an American HVAC engineer, I switch back and forth so often I barely notice anymore.
 
Allow me to simplify.

How do I figure out how many Newtons are required to lift a 500lb weight a distance of 40' in the air.

'GPE' is was it was called 30 years ago in high school physics. We wrote it as such.

Thanks for any help
 
Simply google the lb:N conversion factor and multiply.

Height is now irrelevant of course.
 
RobVG said:
Allow me to simplify.

How do I figure out how many Newtons are required to lift a 500lb weight a distance of 40' in the air.

'GPE' is was it was called 30 years ago in high school physics. We wrote it as such.

Thanks for any help

You just made a mistake. "Newtons" is not a unit of energy.
Newtons is a unit of force, just like pounds (lbs).
The energy unit in the English system is foot-pounds (ft-lbs). The change in GPE could be measured in joules or ft-lbs.
 
MY GAWD!

Who are you guys? Are you just a bunch of snotty children?

russ_watters- "Height is now irrelevant of course."

W=F*D Work is measured in Joules. How the hell can D be irrelevant?

And Darwin123, yours is the most rude response I have ever gotten to an inquiry. And then you follow up with this-

"You just made a mistake. "Newtons" is not a unit of energy.
Newtons is a unit of force, just like pounds (lbs)."

I was asking what "force" is required to lift the weight."

Try reading my second question again if it's within your limited ability to comprehend- you troll.

I will happily Google what I need and find my own answers. You can be damn sure I won't search for answers again on this forum.
 
  • #10
RobVG said:
W=F*D Work is measured in Joules. How the hell can D be irrelevant?

"You just made a mistake. "Newtons" is not a unit of energy.
Newtons is a unit of force, just like pounds (lbs)."

I was asking what "force" is required to lift the weight."

Well, the thing is (and I think this might be what caused the confusion), 500 lbs IS the force. The pound is a unit of force, not a unit of mass. In particular, 500 lbs is the weight of the object, and its "weight" is defined as the force with which Earth's gravity pulls down on it. So...you already know the force.

You know the force, and you know the distance, so all you have to do is multiply these two numbers, and you'll arrive at your answer for the increase in potential energy. Now, since you want the answer in joules, which are Newton-metres, a metric unit, it's probably best if you first convert both the force and the distance to metric units. So, as russ suggested, all you have to do is look up the conversion factors between pounds and Newtons, and between metres and feet.

With his comment about the height being irrelevant, what russ was trying to get at was that if all you wanted know was the force and not the GPE (which is what you implied in post #6), then the height was no longer required as a value in solving the problem. To get the force in Newtons, all you have to do is convert the 500 lbs of force to Newtons. I think that's all he was saying, and no rudeness was intended.

I strongly advise you to give this forum a chance. You'll find no better place for accurate physics advice and help online. Please let me know if you need any further clarification!
 
  • #11
I understand the question and we use gpe all the time.
We do not use lb and feet though.
I don't know why some people have to be rude
 
  • #12
RobVG said:
MY GAWD!

Who are you guys? Are you just a bunch of snotty children?
Calm down. We're trying to help, but you are not making it very easy to help you.
russ_watters- "Height is now irrelevant of course."

W=F*D Work is measured in Joules. How the hell can D be irrelevant?
You changed the question in the post I was quoting, saying you were no longer interested in work (Joules) and now were only interested in force (Newtons).

Darwin123 pointed that error out -- which is most certainly not rude.
I will happily Google what I need and find my own answers. You can be damn sure I won't search for answers again on this forum.
If the help we've given you so far isn't good enough to get you what you need, then you may well be beyond our ability to help. Good luck. Thread closed.
 
Last edited:

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 14 ·
Replies
14
Views
19K
  • · Replies 4 ·
Replies
4
Views
8K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K