Calculating Horizontal Force on a Frictionless Ramp: A 100kg Crate Problem

[the_EVIL]

Homework Statement

A 100kg crate is pushed at a constant speed up a frictionless 30 degree inclined ramp. What constant horizontal force is required? what force is exerted on the crate by the ramp?

Homework Equations

Fg parallel= mgsin(theta), Fg Perpindicular=mgcos(theta), Constant speed-->a=0m/s2

The Attempt at a Solution

Fg=mg
=9.8x100
=980N
Fg parallel=980sin(30)
=490N

Fg perpindicular= 980cos(30)
=849N

I have no idea what to do next! Please help me out here if you can! Any contribution appreciated!

 

[Delphi51]

Welcome to PF, Evil!
The push must equal the parallel (down the ramp) component.
The block pushes on the ramp (straight in) with the perpendicular component. No more calcs to do!

 

[the_EVIL]

Thanks for the welcome! And the guidance on this question! Looks like these forums could come in really handy in the next little while!

 

[Delphi51]

Indeed! Be sure you don't miss out on the struggle part - give it a darn good try yourself before posting. We're here to save you from wasting time but we must not prevent you from learning in the struggle.