Calculating Impact Depth & Speed for 1kg Steel Piece

In summary, we are discussing the calculation of the depth of impact when a 1kg piece of steel hits a steel surface with a speed of 5m/s. We are assuming that the steel has a material shear strength of 0.345 kN/mm2. The second question is how much speed is needed for the same steel piece to penetrate a 1cm thick steel sheet using the same shear strength, and what is the speed of the 1kg steel piece after penetration? The request has been made to show the work and to post the original question if it is a homework or textbook problem.
  • #1
jozne
1
0
If 1kg piece of steel hits steel surface with speed of 5m/s, how can you
calculate the depth of the impact? Let's assume that the steel has
0.345 kN/mm2 material shear strength.

Second question is that how much speed is needed to that same steel piece
to penetrate 1cm thick steel sheet (using the same shear strength), and
what's the speed of the 1kg steel piece after the penetration?
 
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  • #2
jozne said:
If 1kg piece of steel hits steel surface with speed of 5m/s, how can you calculate the depth of the impact?
Please show your work first. If this is a homework/textbook problem, please post the original question EXACTLY as it was given to you.
 
  • #3


To calculate the depth of the impact for a 1kg steel piece hitting a steel surface with a speed of 5m/s, we can use the equation for kinetic energy (KE = 1/2mv^2) and the equation for work (W = F*d) to find the impact depth (d). First, we need to convert the speed from m/s to mm/s (1m = 1000mm), so 5m/s = 5000mm/s. Then, we can rearrange the equations to solve for the impact depth:

KE = 1/2mv^2
KE = 1/2 * 1kg * (5000mm/s)^2
KE = 1/2 * 1kg * 25,000,000mm^2/s^2
KE = 12,500,000mm^2/s^2

W = F*d
12,500,000mm^2/s^2 = 0.345kN/mm^2 * d
d = 12,500,000mm^2/s^2 / 0.345kN/mm^2
d = 36,231,884mm = 36.2m

Therefore, the impact depth for a 1kg steel piece hitting a steel surface with a speed of 5m/s is approximately 36.2m.

For the second question, we can use the same equations and solve for the speed (v) needed for the 1kg steel piece to penetrate a 1cm thick steel sheet. We also need to convert the thickness from cm to mm (1cm = 10mm).

KE = 1/2mv^2
W = F*d

1cm = 10mm
W = F*d
W = 0.345kN/mm^2 * 10mm
W = 3.45kN/mm

KE = 1/2mv^2
3.45kN/mm = 1/2 * 1kg * v^2
v = √(3.45kN/mm * 2 / 1kg)
v = √(6.9kN/mm)
v = 2.6kN/mm

Therefore, the speed needed for the 1kg steel piece to penetrate a 1cm thick steel sheet is approximately 2.6kN/mm. As for the
 

FAQ: Calculating Impact Depth & Speed for 1kg Steel Piece

1. How do you calculate the impact depth of a 1kg steel piece?

The impact depth of a 1kg steel piece can be calculated using the formula d = (E * m * v^2) / (2 * p * A * y), where d is the impact depth, E is the density of the steel, m is the mass of the steel piece, v is the impact speed, p is the density of the target material, A is the cross-sectional area of the steel piece, and y is the yield strength of the steel.

2. What is the impact speed of a 1kg steel piece?

The impact speed of a 1kg steel piece can be calculated using the formula v = √(2 * d * p * A * y) / (E * m), where v is the impact speed, d is the impact depth, p is the density of the target material, A is the cross-sectional area of the steel piece, y is the yield strength of the steel, and E is the density of the steel.

3. How does the impact depth and speed of a 1kg steel piece affect its penetration ability?

The impact depth and speed of a 1kg steel piece are directly related to its penetration ability. A higher impact speed and depth will result in a deeper and more forceful penetration into the target material.

4. What are the units of measurement for impact depth and speed?

The units of measurement for impact depth are typically in meters (m) or millimeters (mm). The units for impact speed are typically in meters per second (m/s) or kilometers per hour (km/h).

5. How accurate are the calculations for impact depth and speed of a 1kg steel piece?

The accuracy of the calculations for impact depth and speed of a 1kg steel piece depends on the accuracy of the input values used in the formulas, such as the density and yield strength of the steel. It is important to use accurate and precise measurements in order to obtain more accurate results.

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