Calculating impedance for parallel circuit

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SUMMARY

The discussion focuses on calculating impedance in a parallel circuit using complex numbers. The correct method involves converting the expression (a + ib)/(p + iq) into standard form by multiplying both the numerator and denominator by the complex conjugate of the denominator. This results in the expression simplifying to 4 + j8, confirming the solution. Users are encouraged to utilize this method for accurate impedance calculations.

PREREQUISITES
  • Understanding of complex numbers and their operations
  • Familiarity with impedance in electrical circuits
  • Knowledge of complex conjugates
  • Basic proficiency in using scientific calculators for complex calculations
NEXT STEPS
  • Study the application of complex numbers in electrical engineering
  • Learn about calculating total impedance in parallel circuits
  • Explore the use of scientific calculators for complex number operations
  • Investigate the significance of the complex conjugate in circuit analysis
USEFUL FOR

Electrical engineers, students studying circuit theory, and anyone involved in analyzing parallel circuits using complex impedance calculations.

spiderabbit
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Hi there,

Below shows the solution to the circuit.
However i am confused about how to solve the eq in red box.

http://img208.imageshack.us/img208/2797/123vv.jpg

do i need to solve it by calculator or more work needs to be done?

If it's by calculator i am using sharp and i couldn't get the correct answer.

Please advice. Thanks.
 

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Welcome to PF!

Hi spiderabbit! Welcome to PF! :smile:

The trick for putting (a + ib)/(p + iq) into standard form is to myltiply both top and bootm by the complex conjugate of the bottom …

(a + ib)/(p + iq) = (a + ib)(p - iq)/(p2 + q2) :wink:

That does give your answer of 4 + j8 … what is worrying you?
 

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